PAT 甲级 1020. Tree Traversals
2017-06-12 17:49
337 查看
原题传送门
树的遍历 之 已知后序和中序输出层序
附原题:
Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=30), the total number of nodes in the binary tree. The second line gives the postorder sequence and the third line gives the inorder sequence. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding binary tree. All the numbers in a line must be separated by exactly one space, and there must be no extra space at the end of the line.
Sample Input:
7
2 3 1 5 7 6 4
1 2 3 4 5 6 7
Sample Output:
4 1 6 3 5 7 2
树的遍历 之 已知后序和中序输出层序
#include <iostream> #include <vector> using namespace std; vector<int> post, in, level(100000, -1); void pre(int root, int start, int end, int index) { if(start > end) return; int i = start; while(i < end && in[i] != post[root]) ++i; level[index] = post[root]; pre(root-1-(end-i), start, i-1, 2*index+1); pre(root-1, i+1, end, 2*index+2); } int main(int argc, const char * argv[]) { int n; cin >> n; post.resize(n); in.resize(n); for(int i = 0; i < n; ++i) cin >> post[i]; for(int i = 0; i < n; ++i) cin >> in[i]; pre(n-1, 0, n-1, 0); cout << level[0]; for(int i = 1; i < level.size(); ++i) { if(level[i] != -1) cout << " " << level[i]; } return 0; }
附原题:
Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=30), the total number of nodes in the binary tree. The second line gives the postorder sequence and the third line gives the inorder sequence. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding binary tree. All the numbers in a line must be separated by exactly one space, and there must be no extra space at the end of the line.
Sample Input:
7
2 3 1 5 7 6 4
1 2 3 4 5 6 7
Sample Output:
4 1 6 3 5 7 2
相关文章推荐
- pat甲级1002
- PAT 甲级 1078 Hashing
- PAT - 甲级 - 1018. Public Bike Management (30)(Dijkstra+DFS)
- PAT 甲级练习 1002
- PAT甲级1002题解
- PAT - 甲级 - 1086. Tree Traversals Again (25)(已知中序+先序求后序)
- pat甲级1009:Product of Polynomials
- PAT甲级 1055. The World's Richest (25)
- PAT甲级 1064. Complete Binary Search Tree (30)
- PAT - 甲级 - 1125. Chain the Ropes (25)
- PAT - 甲级 - 1051. Pop Sequence (25)(模拟)
- PAT - 甲级 - 1105. Spiral Matrix (25)(模拟)
- pat 甲级 1023-1026
- 1101. Quick Sort (25)-PAT甲级真题
- PAT - 甲级 - 1077. Kuchiguse (20)(字符串处理)
- PAT - 甲级 - 1032. Sharing (25)(链表)
- 1009. Product of Polynomials (25)-PAT甲级真题
- PAT甲级1008. Elevator (20)
- 1077. Kuchiguse (20)-PAT甲级真题
- 1052. Linked List Sorting (25)-PAT甲级真题