您的位置:首页 > 其它

leetcode 91. Decode Ways

2017-06-11 23:41 363 查看
A message containing letters from A-Z is being encoded to numbers using the following mapping:

'A' -> 1
'B' -> 2
...
'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.

For example,
Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).

The number of ways decoding "12" is 2.


两个状态,该点是一位还是两位,

恶心的是要注意,0的情况,0是一位不合法,01时两位不合法,这题AC率低主要是这两种情况的判断

public class Solution {
public int numDecodings(String s) {
if(s==null || s.length()==0) return 0;
int len = s.length();
int[] one = new int[len];
int[] two = new int[len];

if(s.charAt(0)=='0'){
one[0] = 0;
}else{
one[0] = 1;
}
two[0] = 0;
for(int i=1; i<len; i++){
if(s.charAt(i)=='0'){
one[i] = 0;
}else{
one[i] = one[i-1] + two[i-1];
}

if(s.charAt(i-1)=='0'){
two[i]=0;
}else{
int t = Integer.valueOf(s.substring(i-1,i+1));
if(t>26 || t <=0){
two[i] = 0;
}else{

if(i-2>=0){
two[i] = one[i-2] + two[i-2];
}else{
two[i] = 1;
}
}
}

}
return one[len-1]+two[len-1];
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode