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leetcode 139. Word Break

2017-06-11 16:14 375 查看
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. You may assume the dictionary does not contain duplicate words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

UPDATE (2017/1/4):
The wordDict parameter had been changed to a list of strings (instead of a set of strings). Please reload the code definition to get the latest changes.


采用动态规划,dp[i]表示目标字符串s中0-i是否合法

public class Solution {
public boolean wordBreak(String s, List<String> wordDict) {
boolean[] res = new boolean[s.length() +1];
res[0] = true;
for(int i=1; i < s.length()+1; i++){
for(String str : wordDict){
if(str.length() <=i){
if(res[i-str.length()]){
if(s.substring(i-str.length(), i).equals(str)){
res[i] = true;
break;
}
}
}
}
}
return res[s.length()];
}
}
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标签:  leetcode