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LEETCODE 37. Sudoku Solver

2017-06-04 23:02 323 查看

题目大意

是leetcode36的进阶版,要解出数独的答案



解题思路

就是用递归,无奈太渣,弄错了边界条件,而且思路还不够清晰,递归函数返回类型一开始写成void了,导致board里面的内容总是被清空,后来改成bool,并在清空内容之前做一下判断。

实现代码

class Solution {
public:
void solveSudoku(vector<vector<char>>& board) {
bool rowFlag[9][9] = {false}, colFlag[9][9] = {false}, blockFlag[9][9] = {false};
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
if (board[i][j] != '.') {
rowFlag[board[i][j] - '1'][i] = true;
colFlag[board[i][j] - '1'][j] = true;
blockFlag[board[i][j] - '1'][i / 3 * 3 + j / 3] = true;
}
}
}
recursion(board, rowFlag, colFlag, blockFlag, 0, 0);
}
private:
bool recursion(vector<vector<char>>& board, bool rowFlag[9][9], bool colFlag[9][9], bool blockFlag[9][9], int row, int col) {
if (row == 9 && col == 0) {
return true;
}
if (board[row][col] != '.') {
col++;
if (col > 8) {
col = 0;
row++;
}
return recursion(board, rowFlag, colFlag, blockFlag, row, col);
} else {
for (int i = 1; i <= 9; i++) {
if (!rowFlag[i - 1][row] && !colFlag[i - 1][col] && !blockFlag[i - 1][row / 3 * 3 + col / 3]) {
rowFlag[i - 1][row] = true;
colFlag[i - 1][col] = true;
blockFlag[i - 1][row / 3 * 3 + col / 3] = true;
board[row][col] = i + '0';
int newRow = row, newCol = col + 1;
if (newCol > 8) {
newCol = 0;
newRow++;
}
bool flag = recursion(board, rowFlag, colFlag, blockFlag, newRow, newCol);
if (!flag) {
rowFlag[i - 1][row] = false;
colFlag[i - 1][col] = false;
blockFlag[i - 1][row / 3 * 3 + col / 3] = false;
board[row][col] = '.';
} else {
return true;
}
}
}
return false;
}
}
};
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