用tensorflow实现MNIST(手写数字识别)
2017-06-01 16:48
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自动下载和导入MNIST数据集
# Copyright 2015 The TensorFlow Authors. All Rights Reserved. # # Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. # See the License for the specific language governing permissions and # limitations under the License. # ============================================================================== """Functions for downloading and reading MNIST data.""" from __future__ import absolute_import from __future__ import division from __future__ import print_function import gzip import os import tempfile import numpy from six.moves import urllib from six.moves import xrange # pylint: disable=redefined-builtin import tensorflow as tf from tensorflow.contrib.learn.python.learn.datasets.mnist import read_data_sets
MNIST(手写数字识别)
#!usr/bin/python #coding:utf-8 import input_data import tensorflow as tf #权值初始化 def weight_variable(shape): initial = tf.truncated_normal(shape, stddev=0.1) #随机数 return tf.Variable(initial) def bias_variable(shape): initial = tf.constant(0.1, shape=shape) return tf.Variable(initial) #卷积 def conv2d(x, W): return tf.nn.conv2d(x, W, strides=[1, 1, 1, 1], padding='SAME') #池化 def max_pool_2x2(x): return tf.nn.max_pool(x, ksize=[1, 2, 2, 1], strides=[1, 2, 2, 1], padding='SAME') mnist = input_data.read_data_sets("MNIST_data/", one_hot=True) sess = tf.InteractiveSession() x = tf.placeholder(tf.float32, [None, 784]) #占位符,为输入图像和输出类别创建节点 y_ = tf.placeholder("float", shape=[None, 10]) x_image = tf.reshape(x, [-1,28,28,1]) #-1为缺省值,由python根据实际情况推算 #第一层卷积池化 W_conv1 = weight_variable([5, 5, 1, 32])#前两个维度是patch的大小,接着是输入的通道数目,最后是输出的通道数目 b_conv1 = bias_variable([32]) # 一句话概括:不用simgoid和tanh作为激活函数,而用ReLU作为激活函数的原因是:加速收敛。 # 因为sigmoid和tanh都是饱和(saturating)的。何为饱和?个人理解是把这两者的函数曲线和导数曲线plot出来就知道了: #他们的导数都是倒过来的碗状,也就是,越接近目标,对应的导数越小。而ReLu的导数对于大于0的部分恒为1。于是ReLU确实 #可以在BP的时候能够将梯度很好地传到较前面的网络。ReLU(线性纠正函数)取代sigmoid函数去激活神经元 h_conv1 = tf.nn.relu(conv2d(x_image, W_conv1) + b_conv1) h_pool1 = max_pool_2x2(h_conv1) #第二层卷积池化 W_conv2 = weight_variable([5, 5, 32, 64]) b_conv2 = bias_variable([64]) h_conv2 = tf.nn.relu(conv2d(h_pool1, W_conv2) + b_conv2) h_pool2 = max_pool_2x2(h_conv2) #全连接层 W_fc1 = weight_variable([7 * 7 * 64, 1024]) b_fc1 = bias_variable([1024]) h_pool2_flat = tf.reshape(h_pool2, [-1, 7*7*64]) h_fc1 = tf.nn.relu(tf.matmul(h_pool2_flat, W_fc1) + b_fc1) keep_prob = tf.placeholder("float") #每个神经元被保留下来的概率 h_fc1_drop = tf.nn.dropout(h_fc1, keep_prob) #防止过拟合 #输出层 W_fc2 = weight_variable([1024, 10]) b_fc2 = bias_variable([10]) y_conv=tf.nn.softmax(tf.matmul(h_fc1_drop, W_fc2) + b_fc2)#将任意实值向量映射到0-1范围内,元素总和为1 ##########训练和评估模型########## cross_entropy = -tf.reduce_sum(y_*tf.log(y_conv)) #交叉熵 train_step = tf.train.AdamOptimizer(1e-4).minimize(cross_entropy) #1e-4:学习速率 #tf.argmax给出某个tensor对象在某一维上的其数据最大值所在的索引值 #由于标签向量是由0,1组成,因此最大值1所在的索引位置就是类别标签 correct_prediction = tf.equal(tf.argmax(y_conv,1), tf.argmax(y_,1)) accuracy = tf.reduce_mean(tf.cast(correct_prediction, "float"))#计算均值 sess.run(tf.initialize_all_variables()) for i in range(1000): batch = mnist.train.next_batch(50) if i%100 == 0: train_accuracy = accuracy.eval(feed_dict={ x:batch[0], y_: batch[1], keep_prob: 1.0}) print "step %d, training accuracy %g"%(i, train_accuracy) train_step.run(feed_dict={x: batch[0], y_: batch[1], keep_prob: 0.5}) print "test accuracy %g"%accuracy.eval(feed_dict={x: mnist.test.images, y_: mnist.test.labels, keep_prob: 1.0})
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