逻辑位运算

//正数的补码：与原码相同。
//负数的补码：符号位为1，其余位为该数绝对值的原码按位取反；然后整个数加1。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
int bit_1,bit_2,bit_3;
bit_1 = 12;             //00001100
bit_2 = 7;              //00000111
bit_3 = -8;             //11111000

printf("AND运算：%d\n",bit_1 & bit_2);
printf("OR运算：%d\n",bit_1 | bit_2);
printf("XOR运算：%d\n",bit_1 ^ bit_2);
printf("NO运算：%d\n", ~ bit_2);
printf("NO运算：%d\n", ~ bit_3);

system("pause");
return 0;
}

#include <stdio.h>
#include <stdlib.h>

#define BIT2 (0x01<<2)

int main()
{
int a=3;
//  a |= BIT2;           //设置BIT2位
//  a &= ~BIT2;          //清除BIT2位
a &= (a-1);          //清除最后一位
printf("SET:%d\n",a);
system("pause");
}

#include <stdio.h>
#include <stdlib.h>

int main()
{
int x,y;

printf("Input two dates:");
scanf("%d %d",&x,&y);
printf("x=%d,y=%d\n",x,y);
x=x^y;
y=x^y;
x=x^y;
printf("x=%d,y=%d\n",x,y);
system("pause");
}