Codeforces Round #345 (Div. 2) B 思维题
2017-05-20 10:08
267 查看
http://codeforces.com/contest/651/problem/B题意:给你n个数字,要求你合理的按顺序排列这些数字,使得满足a[i+1]>a[i]的个数尽可能多,输出最多的个数;分析:有n个数字,那么,有n-1个间隔,统计这些数字中重复次数最多的数字出现的次数为m次,那么其中就有m-1个间隔是无效的。(神思路)
相关文章推荐
- codeforces round 345 div2 Image Interview 贪心 + 二分
- Codeforces Round #418 (Div. 2) D. An overnight dance in discotheque(思维 贪心)
- Codeforces Round #345 (Div. 2) B. Beautiful Paintings 暴力
- 【前缀和 && 思维转换】ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined)Molly's Chemicals
- Codeforces Round #218 (Div. 2) E. Subway Innovation(思维 前缀和)
- Codeforces Beta Round #32 (Div. 2) C (math+思维)
- Codeforces Round #397(Div. 1 + Div. 2 combined)E. Tree Folding【思维+Dfs】dalao们的解法真巧妙系列QAQ
- Codeforces Round #345 (Div. 2) [Codeforces651]
- Codeforces Round #345 (Div. 2) D. Image Preview 暴力 二分
- Codeforces Round #272 (Div. 2) C. Dreamoon and Sums (数学 思维)
- Codeforces Round #345 (Div. 2) D. Image Preview
- 【Codeforces Round 263 (Div 2)C】【贪心 哈弗曼思维】Appleman and Toastman 每个非1size子树延展为2子树的最大权
- Codeforces Round #350 (Div. 2) C. Cinema __ sortings, 思维题,many data
- Codeforces Round #345 (Div. 2) E. Table Compression 并查集
- Codeforces Round #345 (Div. 2)
- Codeforces Round #418 (Div. 2) A+B(思维)
- Codeforces Round #433 (Div. 1) B Jury Meeting(思维)
- Codeforces Round #272 (Div. 2) D. Dreamoon and Sets (思维 数学 规律)
- Codeforces Round #421 (Div. 1):B. Mister B and PR Shifts 思维,乱搞
- Codeforces Round #253 (Div. 2) E. Artem and Array (思维)