[leetcode: Python]

Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

Example:

Input:
[1,2,3]

Output:
3

Explanation:
Only three moves are needed (remember each move increments two elements):

[1,2,3]  =>  [2,3,3]  =>  [3,4,3]  =>  [4,4,4]

题目大意：

给定一个长度为n的非空整数数组，计算最少需要多少次移动可以使所有元素相等，一次移动是指将n - 1个元素加1。

解题思路：

一次移动将n - 1个元素加1，等价于将剩下的1个元素减1。

因此累加数组中各元素与最小值之差即可。

方法一：75ms

class Solution(object):
def minMoves(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
return sum(nums) - min(nums) * len(nums)