codeforces 808B——Average Sleep Time
2017-05-16 08:17
381 查看
B. Average Sleep Time
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts k days!
When Polycarp went to a doctor with his problem, the doctor asked him about his sleeping schedule (more specifically, the average amount of hours of sleep per week). Luckily, Polycarp kept records of sleep times for the last n days.
So now he has a sequence a1, a2, ..., an,
where ai is
the sleep time on the i-th day.
The number of records is so large that Polycarp is unable to calculate the average value by himself. Thus he is asking you to help him with the calculations. To get the average Polycarp is going to consider k consecutive
days as a week. So there will be n - k + 1 weeks to take into consideration. For example, if k = 2, n = 3 and a = [3, 4, 7],
then the result is
.
You should write a program which will calculate average sleep times of Polycarp over all weeks.
Input
The first line contains two integer numbers n and k (1 ≤ k ≤ n ≤ 2·105).
The second line contains n integer numbers a1, a2, ..., an (1 ≤ ai ≤ 105).
Output
Output average sleeping time over all weeks.
The answer is considered to be correct if its absolute or relative error does not exceed 10 - 6.
In particular, it is enough to output real number with at least 6 digits after the decimal point.
Examples
input
output
input
output
input
output
Note
In the third example there are n - k + 1 = 7 weeks, so the answer is sums of all weeks divided by 7.
模拟一下就行了
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <iomanip>
using namespace std;
#define _ ios::sync_with_stdio(false)
const int MAXN = 200010;
const int INF=0x7fffffff;
int n,k;
double a[MAXN];
double sum=0;
int main(){
scanf("%d%d",&n,&k);
a[0]=0;
double s=0;
for(int i=1;i<=n;i++){
scanf("%lf",a+i);
sum+=a[i];
if(i>=k){
sum-=a[i-k];
s+=sum;
}
}
double y=n-k+1;
s/=y;
printf("%.12f\n",s);
}
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts k days!
When Polycarp went to a doctor with his problem, the doctor asked him about his sleeping schedule (more specifically, the average amount of hours of sleep per week). Luckily, Polycarp kept records of sleep times for the last n days.
So now he has a sequence a1, a2, ..., an,
where ai is
the sleep time on the i-th day.
The number of records is so large that Polycarp is unable to calculate the average value by himself. Thus he is asking you to help him with the calculations. To get the average Polycarp is going to consider k consecutive
days as a week. So there will be n - k + 1 weeks to take into consideration. For example, if k = 2, n = 3 and a = [3, 4, 7],
then the result is
.
You should write a program which will calculate average sleep times of Polycarp over all weeks.
Input
The first line contains two integer numbers n and k (1 ≤ k ≤ n ≤ 2·105).
The second line contains n integer numbers a1, a2, ..., an (1 ≤ ai ≤ 105).
Output
Output average sleeping time over all weeks.
The answer is considered to be correct if its absolute or relative error does not exceed 10 - 6.
In particular, it is enough to output real number with at least 6 digits after the decimal point.
Examples
input
3 2 3 4 7
output
9.0000000000
input
1 1 10
output
10.0000000000
input
8 2 1 2 4 100000 123 456 789 1
output
28964.2857142857
Note
In the third example there are n - k + 1 = 7 weeks, so the answer is sums of all weeks divided by 7.
模拟一下就行了
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <iomanip>
using namespace std;
#define _ ios::sync_with_stdio(false)
const int MAXN = 200010;
const int INF=0x7fffffff;
int n,k;
double a[MAXN];
double sum=0;
int main(){
scanf("%d%d",&n,&k);
a[0]=0;
double s=0;
for(int i=1;i<=n;i++){
scanf("%lf",a+i);
sum+=a[i];
if(i>=k){
sum-=a[i-k];
s+=sum;
}
}
double y=n-k+1;
s/=y;
printf("%.12f\n",s);
}
相关文章推荐
- 【codeforces 808】B.Average Sleep Time
- Codeforces 808B——Average Sleep Time——思维
- 【Codeforces 808 B. Average Sleep Time】+ 前缀和
- 【Codeforces 808B】【容斥原理】Average Sleep Time 题解
- 808B - Average Sleep Time
- codeforces 808B - Average Sleep Time
- codeforces——808B——Average Sleep Time
- Codeforces Educational Codeforces Round 21 [5.30] Tea Party&Array Division&Average Sleep Time&Lucky
- Educational Codeforces Round 21 B. Average Sleep Time
- CF#808 B. Average Sleep Time(水题)
- Educational Codeforces Round 21 B. Average Sleep Time
- [CF808B] Average Sleep Time([强行]树状数组,数学)
- codeforces Educational Codeforces Round 21 B. Average Sleep Time
- B. Average Sleep Time
- it's time go to sleep ,i will be continue!
- Time::HiRes模块中sleep的使用
- python基础编程_8_暂停预定时间,time.sleep( ),时间的格式化
- codeforces——808A——Lucky Year
- CodeForces 343C Read Time 二分+贪心
- go runtime.Gosched() 和 time.Sleep() 做协程切换