[Leetcode]_27 Remove Element
2017-05-15 22:15
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/** * Index: 27 * Title: Remove Element * Author: ltree98 **/
记录不重复的序列号,然后往前并。
class Solution { public: int removeElement(vector<int>& nums, int val) { int index = 0, len = nums.size(); for(int i = 0; i < len ; i++) if(nums[i] != val) nums[index++] = nums[i]; return index; } };
从后往前遍历,如果是目标值,跟尾部的值交换(根据出现目标值的个数)
class Solution { public: int removeElement(vector<int>& nums, int val) { int repeat = 0, len = nums.size() - 1; for(int i = len; i >= 0; i--) { if(nums[i] == val) { nums[i] ^= nums[len-repeat]; nums[len-repeat] ^= nums[i]; nums[i] ^= nums[len-repeat]; ++repeat; } } return (len - repeat + 1); } };
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