HDU 2054 A == B ?(找小数点)
2017-05-13 19:26
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2054
Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
Sample Output
思路:
此题关键是找小数点,找到小数点把最后面无效的零去掉再比較就OK。
代码例如以下:
Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 2 2 2 3 3 4 3
Sample Output
NO YES YES NO
思路:
此题关键是找小数点,找到小数点把最后面无效的零去掉再比較就OK。
代码例如以下:
#include <cstdio> #include <cstring> char a[100017], b[100017]; void re(char s[]) { int len = strlen(s); int p = 0; for(int i = 0; i < len; i++) { if(s[i] == '.') { p = 1; break; } } if(p) { for(int i = len-1; i >= 0; i--) { if(s[i] == '0') s[i] = '\0'; else break; len--; } if(s[len-1] == '.') s[len-1] = '\0'; } } int main() { while(~scanf("%s%s",a,b)) { re(a); // printf("%s\n",a); re(b); // printf("%s\n",b); if(strcmp(a,b)) printf("NO\n"); else printf("YES\n"); } return 0; }
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