[Ural1099]工作安排 带花树

题目大意

题解:

求解一般图最大匹配.
直接使用带花树即可.
(带花树也是刚学)...

马上写带花树的ppt，会很通俗易懂.
(充分证明了本苣智商不够，写不出高深的课件)

如果有想要的依然可以直接私信我 QAQ

带花树模板

#include <cstdio>
#include <cstring>
#include <algorithm>
typedef long long ll;
inline void read(int &x){
x=0;char ch;bool flag = false;
while(ch=getchar(),ch<'!');if(ch == '-') ch=getchar(),flag = true;
while(x=10*x+ch-'0',ch=getchar(),ch>'!');if(flag) x=-x;
}
#define rg register int
#define rep(i,a,b) for(rg i=(a);i<=(b);++i)
#define per(i,a,b) for(rg i=(a);i>=(b);--i)
const int maxn = 256;
int n;
bool map[maxn][maxn],inq[maxn],inBlo[maxn],mark[maxn];
int link[maxn],fa[maxn],belong[maxn],q[maxn],l,r;
inline void bloom(int x,int y){
rep(i,0,n) mark[i] = inBlo[i] = false;
#define nx(x) fa[link[(x)]]
int lca;
for(rg i=x;i;i=nx(i)) mark[i = belong[i]] = true;
for(rg i=y;i;i=nx(i)){
i = belong[i];
if(mark[i]){lca = i;break;}
}
for(rg i=x;belong[i] != lca;i=nx(i)){
if(belong[nx(i)] != lca) fa[nx(i)] = link[i];
inBlo[belong[i]] = inBlo[belong[link[i]]] = true;
}
for(rg i=y;belong[i] != lca;i=nx(i)){
if(belong[nx(i)] != lca) fa[nx(i)] = link[i];
inBlo[belong[i]] = inBlo[belong[link[i]]] = true;
}
#undef nx
if(belong[x] != lca) fa[x] = y;
if(belong[y] != lca) fa[y] = x;
rep(i,1,n) if(inBlo[belong[i]]){
belong[i] = lca;
if(!inq[i]) inq[q[++r] = i] = true;
}
}
inline void modify(int s){
int x,y,z = s;
while(z){
y = fa[z];x = link[y];
link[y] = z;link[z] = y;
z = x;
}
}
inline void bfs(int s){
rep(i,0,n){
fa[i] = inq[i] = 0;
belong[i] = i;
}
l = 0;r = -1;q[++r] = s;
inq[s] = true;
while(l <= r){
int u = q[l++];
rep(v,1,n){
if(map[u][v] == 0 || belong[u] == belong[v] || link[u] == v) continue;
if(s == v || link[v] && fa[link[v]]) bloom(u,v);
else if(fa[v] == 0){
fa[v] = u;
if(link[v] != 0){
q[++r] = link[v];
inq[link[v]] = true;
}else{
modify(v);
return ;
}
}
}
}return ;
}
int main(){
read(n);int u,v;
while(scanf("%d%d",&u,&v) != EOF){
map[u][v] = map[v][u] = true;
}
rep(i,1,n) if(link[i] == 0) bfs(i);
int ans = 0;
rep(i,1,n) if(link[i] != 0) ++ ans;
printf("%d\n",ans);
rep(i,1,n){
if(link[i] > i) printf("%d %d\n",i,link[i]);
}
return 0;
}