PAT 1022. D进制的A+B java实现

输入两个非负10进制整数A和B(<=230-1)，输出A+B的D (1 < D <= 10)进制数。输入格式：输入在一行中依次给出3个整数A、B和D。输出格式：输出A+B的D进制数。输入样例：

123 456 8

输出样例：1103

import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner scanner = new Scanner(System.in);
        int a=scanner.nextInt();
        int b=scanner.nextInt();
        int d=scanner.nextInt();
        int c= a+b;
        int bigInteger1;
        String string="";
        while(true){
            bigInteger1 = c%d;
            c=c/d;
            string =bigInteger1+string;
            if(c==0){
                System.out.println(string);
                break;
            }
        }
    }
}