Splay树（多操作）——POJ 3580 SuperMemo

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SuperMemo

Time Limit: 5000MS		Memory Limit: 65536K
Total Submissions: 11309		Accepted: 3545
Case Time Limit: 2000MS

Description

Your friend, Jackson is invited to a TV show called SuperMemo in which the participant is told to play a memorizing game. At first, the host tells the participant a sequence of numbers, {A1,A2,
... An}. Then the host performs a series of operations and queries on the sequence which consists:

ADD x y D: Add D to each number in sub-sequence {Ax ...Ay}. For example, performing "ADD 2 4 1" on {1, 2, 3, 4, 5} results
in {1, 3, 4, 5, 5}
REVERSE x y: reverse the sub-sequence {Ax ...Ay}. For example, performing "REVERSE 2 4" on {1, 2, 3, 4, 5} results in {1, 4,
3, 2, 5}
REVOLVE x y T: rotate sub-sequence {Ax ...Ay}
T times. For example, performing "REVOLVE 2 4 2" on {1, 2, 3, 4, 5} results in {1, 3, 4, 2, 5}
INSERT x P: insert P after Ax. For example, performing "INSERT 2 4" on {1, 2, 3, 4, 5} results in {1, 2, 4, 3, 4, 5}
DELETE x: delete Ax. For example, performing "DELETE 2" on {1, 2, 3, 4, 5} results in {1, 3, 4, 5}
MIN x y: query the participant what is the minimum number in sub-sequence {Ax ...Ay}. For example, the correct answer to "MIN
2 4" on {1, 2, 3, 4, 5} is 2

To make the show more interesting, the participant is granted a chance to turn to someone else that means when Jackson feels difficult in answering a query he may call you for help. You task is to watch the TV show and write a program giving the correct
answer to each query in order to assist Jackson whenever he calls.

Input

The first line contains n (n ≤ 100000).

The following n lines describe the sequence.

Then follows M (M ≤ 100000), the numbers of operations and queries.

The following M lines describe the operations and queries.

Output

For each "MIN" query, output the correct answer.

Sample Input

5

题意：

对n个数有6种操作：

1）增值：ADD x y D：区间 [x, y] 的全部值添加D

2）翻转：REVERSE x y：把区间 [x, y] 翻转

3）旋转：REVOLVE x y T：对区间 [x, y]顺时针（T > 0）或逆时针（T < 0）旋转T次

4）插入：INSERT x P：在A[x]后面插入P

5）删除：DELETE x：删除A[x]

6）最值：MIN x y：求区间 [x, y] 内的最小值

思路：

Splay树综合操作；须要注意的地方有：

1、Push_down()。Push_up()的写法。应该在什么地方调用

2、旋转操作的T能够是负数

3、旋转事实上就是把区间的后一段取下放到前面或着把前一段取下放到后面，不难想明确