杭电1029 之 Ignatius and the Princess IV

Ignatius and the Princess IV

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32767 K (Java/Others)

Total Submission(s): 31297 Accepted Submission(s): 13415


[align=left]Problem Description[/align]
"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.

"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.

"But what is the characteristic of the special integer?" Ignatius asks.

"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.

Can you find the special integer for Ignatius?

[align=left]Input[/align]
The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the
N integers. The input is terminated by the end of file.

[align=left]Output[/align]
For each test case, you have to output only one line which contains the special number you have found.

[align=left]Sample Input[/align]

5
1 3 2 3 3
11
1 1 1 1 1 5 5 5 5 5 5
7
1 1 1 1 1 1 1

[align=left]Sample Output[/align]

3
5
1

题意：
给你n个数，打印出现次数最多的数

AC代码如下：
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn=999999+10;

int a[maxn],b[maxn];

int main()
{
int n;
while(cin>>n)
{
memset(b,0,sizeof(b));
int maxi=-1;
int cur=-1;
for(int i=0;i<n;i++) cin>>a[i];
for(int i=0;i<n;i++)
{
b[a[i]]++;
if(b[a[i]]>maxi)
{
maxi=b[a[i]];
cur=a[i];
}
}
cout<<cur<<endl;
}
return 0;
}