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HDOJ-- 2051 Bitset

2017-04-30 23:10 281 查看

Bitset

[b]Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 23412    Accepted Submission(s): 17384
[/b]
[align=left]Problem Description[/align]
Give you a number on base ten,you should output it on base two.(0 < n < 1000)

[align=left]Input[/align]
For each case there is a postive number n on base ten, end of file.

[align=left]Output[/align]
For each case output a number on base two.

[align=left]Sample Input[/align]

1
2


[align=left]Sample Output[/align]

1
10
11
import java.util.Scanner;

public class Bitset {
public static void main(String[] args) {//直接調用Integer.toBinaryString(int i)
Scanner sc=new Scanner(System.in); //以二進制无符号整数返回一个整数参数的字符串形式
while(sc.hasNext()){
int n=sc.nextInt();
System.out.println(Integer.toBinaryString(n));
}
}
}

 
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