【BZOJ 2733】 [HNOI2012]永无乡
2017-04-26 08:15
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思路
并查集+线段树合并时间复杂度O(nlog2n+qlogn)
代码
#include <cstdio> #include <iostream> #include <algorithm> #define mid ((l+r)>>1) using namespace std; const int maxn = 100010; struct node{ int val; node *ch[2]; }pool[maxn*25], *null, *root[maxn]; int fa[maxn], sz[maxn], ct, n, m, q, v[maxn]; node *get(int val){ node *now = &pool[++ct]; now->ch[0] = now->ch[1] = null; now->val = val; return now; } void build(node *now, int l, int r, int pos){ if(l == r) return; int wh = 0; if(pos >= mid+1) wh = 1; now->ch[wh] = get(1); build(now->ch[wh], wh==0?l:mid+1, wh==0?mid:r, pos); } void merge_tree(node *fi, node *se, int l, int r){ if(l == r) return; if(fi->ch[0] == null) fi->ch[0] = se->ch[0]; else if(se->ch[0] != null){ fi->ch[0]->val += se->ch[0]->val; merge_tree(fi->ch[0], se->ch[0], l, mid); } if(fi->ch[1] == null) fi->ch[1] = se->ch[1]; else if(se->ch[1] != null){ fi->ch[1]->val += se->ch[1]->val; merge_tree(fi->ch[1], se->ch[1], mid+1, r); } } int find(int x){return x == fa[x] ? x : fa[x] = find(fa[x]);} void merge_fa(int x, int y){ int fx = find(x), fy = find(y); if(fx == fy) return; if(sz[fx] < sz[fy]) swap(fx, fy); merge_tree(root[fx], root[fy], 1, n); sz[fx] += sz[fy]; fa[fy] = fx; } void que(node *now, int l, int r, int k){ if(l == r){ if(k > now->val) printf("-1\n"); else printf("%d\n", v[l]); return; } if(now->ch[0]->val >= k) que(now->ch[0], l, mid, k); else que(now->ch[1], mid+1, r, k - now->ch[0]->val); } int main(){ null = pool, null->val = 0, null->ch[0] = null->ch[1] = null; scanf("%d%d", &n, &m); for(int i = 1; i <= n; i ++) root[i] = get(0); for(int i = 1; i <= n; i ++) fa[i] = i, sz[i] = 1; for(int i = 1, t; i <= n; i ++){ scanf("%d", &t), v[t] = i; build(root[i], 1, n, t); } for(int i = 1, x, y; i <= m; i ++){ scanf("%d%d", &x, &y); merge_fa(x, y); } scanf("%d", &q); for(int i = 1, x, y; i <= q; i ++){ char ch[5]; scanf("%s%d%d", ch+1, &x, &y); if(ch[1] == 'Q') que(root[find(x)], 1, n, y); else merge_fa(x, y); } return 0; }
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