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201521123040《Java程序设计》第9周学习总结

2017-04-21 23:28 204 查看

1. 本周学习总结

1.1 以你喜欢的方式(思维导图或其他)归纳总结异常相关内容。



2. 书面作业

本次PTA作业题集异常

1.常用异常

题目5-1

1.1 截图你的提交结果(出现学号)



1.2 自己以前编写的代码中经常出现什么异常、需要捕获吗(为什么)?应如何避免?

1.3 什么样的异常要求用户一定要使用捕获处理?

2.处理异常使你的程序更加健壮

题目5-2

2.1 截图你的提交结果(出现学号)



2.2 实验总结

3.throw与throws

题目5-3

3.1 截图你的提交结果(出现学号)



3.2 阅读Integer.parsetInt源代码,结合3.1说说抛出异常时需要传递给调用者一些什么信息?

源代码

public static int parseInt(String s, int radix)
throws NumberFormatException
{
/*
* WARNING: This method may be invoked early during VM initialization
* before IntegerCache is initialized. Care must be taken to not use
* the valueOf method.
*/

if (s == null) {
throw new NumberFormatException("null");
}

if (radix < Character.MIN_RADIX) {
throw new NumberFormatException("radix " + radix +
" less than Character.MIN_RADIX");
}

if (radix > Character.MAX_RADIX) {
throw new NumberFormatException("radix " + radix +
" greater than Character.MAX_RADIX");
}

int result = 0;
boolean negative = false;
int i = 0, len = s.length();
int limit = -Integer.MAX_VALUE;
int multmin;
int digit;

if (len > 0) {
char firstChar = s.charAt(0);
if (firstChar < '0') { // Possible leading "+" or "-"
if (firstChar == '-') {
negative = true;
limit = Integer.MIN_VALUE;
} else if (firstChar != '+')
throw NumberFormatException.forInputString(s);

if (len == 1) // Cannot have lone "+" or "-"
throw NumberFormatException.forInputString(s);
i++;
}
multmin = limit / radix;
while (i < len) {
// Accumulating negatively avoids surprises near MAX_VALUE
digit = Character.digit(s.charAt(i++),radix);
if (digit < 0) {
throw NumberFormatException.forInputString(s);
}
if (result < multmin) {
throw NumberFormatException.forInputString(s);
}
result *= radix;
if (result < limit + digit) {
throw NumberFormatException.forInputString(s);
}
result -= digit;
}
} else {
throw NumberFormatException.forInputString(s);
}
return negative ? result : -result;
}

/**
* Parses the string argument as a signed decimal integer. The
* characters in the string must all be decimal digits, except
* that the first character may be an ASCII minus sign {@code '-'}
* ({@code '\u005Cu002D'}) to indicate a negative value or an
* ASCII plus sign {@code '+'} ({@code '\u005Cu002B'}) to
* indicate a positive value. The resulting integer value is
* returned, exactly as if the argument and the radix 10 were
* given as arguments to the {@link #parseInt(java.lang.String,
* int)} method.
*
* @param s    a {@code String} containing the {@code int}
*             representation to be parsed
* @return     the integer value represented by the argument in decimal.
* @exception  NumberFormatException  if the string does not contain a
*               parsable integer.
*/
public static int parseInt(String s) throws NumberFormatException {
return parseInt(s,10);
}

4.函数题

题目4-1(多种异常的捕获)

3.1 截图你的提交结果(出现学号)



3.2 一个try块中如果可能抛出多种异常,捕获时需要注意些什么?

5.为如下代码加上异常处理

byte[] content = null;

FileInputStream fis = new FileInputStream("testfis.txt");

int bytesAvailabe = fis.available();//获得该文件可用的字节数

if(bytesAvailabe>0){

content = new byte[bytesAvailabe];//创建可容纳文件大小的数组

fis.read(content);//将文件内容读入数组

}

System.out.println(Arrays.toString(content));//打印数组内容

5.1 改正代码,让其可正常运行。注1:里面有多个方法均可能抛出异常。注2:要使用finally关闭资源。

5.2 使用Java7中的try-with-resources来改写上述代码实现自动关闭资源.

3. 码云上代码提交记录

题目集:异常

3.1. 码云代码提交记录

在码云的项目中,依次选择“统计-Commits历史-设置时间段”, 然后搜索并截图

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