Easy 19 Merge Sorted Array（88）

Description

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

Solution

从nums1的尾部开始，从后往前，从大往小的插入元素。有点要注意的是临界情况。

class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
int len=m+n-1;
n--;
m--;
while(n>=0){
nums1[len--]=(nums1[m]>nums2
&&m>=0)?nums1[m--]:nums2[n--];
}
}
};