PAT甲题题解-1029. Median (25)-求两序列的中位数,水的不要不要的
2017-04-19 20:01
513 查看
#include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue> using namespace std; /* 水死了 */ const int maxn=2000000+5; int seq[maxn]; int main() { int n1,n2; scanf("%d",&n1); for(int i=0;i<n1;i++){ scanf("%d",&seq[i]); } scanf("%d",&n2); for(int i=0;i<n2;i++){ scanf("%d",&seq[n1+i]); } sort(seq,seq+n1+n2); int n=n1+n2; int mid; if(n%2==0){ mid=n/2; } else{ mid=n/2+1; } printf("%d\n",seq[mid-1]); return 0; }
View Code
相关文章推荐
- PAT 1029. Median (25) 求2个排序数组的中位数——剔除法
- PAT (Advanced Level) 1029. Median (25) 求两个有序数组的中位数,二分
- [PAT] 1029. Median (25)
- PAT (Advanced Level)1029. Median (25)
- PAT 1029. Median (25)
- PAT (Advanced Level) 1029. Median (25)
- PAT (Advanced Level) Practise 1029 Median (25)
- PAT1029.Median (25)
- PAT-1029 Median (25)
- pat甲级1029. Median (25)
- 2-13. 两个有序序列的中位数(25)(ZJU_PAT 链表 | 数组 )
- PAT-A1029. Median (25)
- 【PAT】1029. Median (25)
- PAT 1029 Median(中位数+归并排序)
- PAT甲 1029. Median (25)
- 【C++】PAT(advanced level)1029. Median (25)
- PAT (Advanced) 1029. Median (25)
- PAT 1029. Median (25)
- PAT_A 1029. Median (25)
- PAT 1029. Median (25)(找出俩个非递减数列的公共的中值,我用优先队列做的)