POJ 1458 Common Subsequence(LCS)
2017-04-18 10:01
417 查看
Common Subsequence
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly
increasing sequence < i1, i2, ..., ik > of indices of X such that for all j = 1,2,...,k, x ij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X
and Y the problem is to find the length of the maximum-length common subsequence of X and Y.
Input
The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.
Output
For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
abcfbc abfcab programming contest abcd mnp
Sample Output
4 2 0
裸题,不解释,不好意思我又刷博客了。。。
1)最长公共子序列的长度的动态规划方程
设有字符串a[0...n],b[0...m],下面就是递推公式。字符串a对应的是二维数组num的行,字符串b对应的是二维数组num的列。
另外,采用二维数组flag来记录下标i和j的走向。数字"1"表示,斜向下;数字"2"表示,水平向右;数字"3"表示,竖直向下。这样便于以后的求解最长公共子序列。
#include <iostream> #include <stdio.h> #include <cstring> using namespace std; int main() { int i,j,dp[2][10086],t; char a[10086],b[10086]; bool now,pre; while(~scanf("%s%s",a,b)) { memset(dp,0,sizeof(dp)); int lena=strlen(a),lenb=strlen(b); for(now=1,pre=0,i=0; i<lena; i++) for(swap(now,pre),j=0; j<lenb; j++) if(a[i]==b[j]) dp[now][j+1]=dp[pre][j]+1; else dp[now][j+1]=dp[pre][j+1]>dp[now][j]?dp[pre][j+1]:dp[now][j]; printf("%d\n",dp[now][lenb]); } return 0; }
相关文章推荐
- Poj 1458 Common Subsequence【LCS】【dp】
- HDU/HDOJ 1159/POJ 1458 Common Subsequence(最长公共子序列LCS,滚动数组)
- POJ 1458 / HDU 1159 / Southeastern Europe 2003 Common Subsequence (DP&LCS)
- POJ 1458 Common Subsequence DP LCS 最长公共子序列
- poj 1458 Common Subsequence --- LCS模板
- poj 1458 Common Subsequence(LCS)
- Poj 1458 Common Subsequence(LCS)
- POJ 1458--Common Subsequence【LCS】
- POJ 1458 Common Subsequence(LCS)
- poj1458-Common Subsequence(最长公共子序列,LCS)
- POJ 1458 Common Subsequence 最长公共子序列(LCS)
- poj 1458 Common Subsequence(LCS)
- poj1458 Common Subsequence【LCS】
- POJ 1458-Common Subsequence(线性dp/LCS)
- Poj 1458 Common Subsequence(LCS)
- HDU 1159 & POJ 1458 Common Subsequence 【LCS】
- Poj 1458 Common Subsequence(LCS)
- HDU 1159 & POJ 1458 Common Subsequence(LCS 最长公共子序列O(nlogn))
- poj - 1458 - Common Subsequence(LCS)
- poj-1458-Common Subsequence(LCS)