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hibernate中的query.uniqueResult()统计返回一个整型数据

2017-04-12 16:23 459 查看
public int selectAll(final String time1,
final String time2, final int cityname, final String airstatus) {
final StringBuffer hql = new StringBuffer(
"select count(air) from TableName air where air.cityname="
+ cityname + " and air.isDelete=0 and air.strtes1=1 and air.airstatus='" + airstatus + "'");
if (time1 != null && !time1.equals("")) {
hql.append(" and air.reportDate >=:time1");
}
if (time2 != null && !time2.equals("")) {
hql.append(" and air.reportDate <=:time2");
}
hql.append(" order by air.cityname asc ");
Number list = this.getHibernateTemplate().execute(
new HibernateCallback() {
public Object doInHibernate(Session session)
throws HibernateException, SQLException {

Query query = session.createQuery(hql.toString());
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");
try {
if (time1 != null && !time1.equals("")) {
query.setDate("time1", df.parse(time1));
}
if (time2 != null && !time2.equals("")) {
query.setDate("time2", df.parse(time2));
}
} catch (ParseException e) {
e.printStackTrace();
}
return query.uniqueResult();
}
});
return list.intValue();
}
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