LeetCode-Easy部分中标签为String 58. Length of Last Word

原题

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = "Hello World",
return 5.

实现代码

方法一

public int LengthOfLastWord1(string s)
{
s = s.Trim(); //去掉前，后空格
if (s == "") return 0;
string[] splitstring = s.Split(' ');
string slast = splitstring[splitstring.Length - 1];
return slast.Length == 0 ? 1 : slast.Length;
}

方法二

public int LengthOfLastWord2(string s)
{
s = s.Trim();
if (s == "") return 0;
for (int i = s.Length-1;i>0; i--)
{
if (s[i] == ' ')
return  s.Length - i - 1;
}
return s.Length;
}