leetcode 58. Length of Last Word

58. Length of Last Word

Description

Given a string s consists of upper/lower-case alphabets and empty space characters

' '

, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s =

"Hello World"

,

return

5

.

这道题看似简单，但情况很多，稍不留意，就花费很多时间都写不对，得特别逐一这种题。得考虑“      ” ，“abc    ”，"a       bn     "等特殊情况

int lengthOfLastWord(char* s) {
int length;
int i;
int precount = 0, count = 0;
length = strlen(s);
if(length == 0) return 0;
for(i = 0; i < length; i++)
{
if(s[i] == ' ') continue;
else{
if(i !=0 && s[i - 1] == ' '){
count = 1;
continue;
}
}
count++;
}
return count;
}