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LeetCode (Reverse Integer)

2017-03-29 09:08 417 查看
Problem:

Reverse digits of an integer.

Example1: x = 123, return 321

Example2: x = -123, return -321

Note:

The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

Answer:

class Solution {
public:
int reverse(int x) {
long long ans=0;
while (x){
ans = ans*10 + x%10;
x/=10;
}
return ans>INT_MAX||ans<INT_MIN?0:ans;
}
};
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