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Shell变量while循环内改变无法传递到循环外

2017-03-24 15:33 357 查看
今天刷Leecode(192 Word frequency)时,遇到一个shell语法问题,记录下来。首先将题目描述和代码呈上
#!/bin/bash

# Write a bash script to calculate the frequency of each word in a text file words.txt.
#
# For simplicity sake, you may assume:
# words.txt contains only lowercase characters and space ' ' characters.
# Each word must consist of lowercase characters only.
# Words are separated by one or more whitespace characters.
#
# For example, assume that words.txt has the following content:
# the day is sunny the the
# the sunny is is
#
# Your script should output the following, sorted by descending frequency:
# the 4
# is 3
# sunny 2
# day 1

# define a map
declare -A map=()

# iterator lines in file
#cat words.txt | while read line
while read line
do
for word in $line
do
echo $word
if [ -z ${map[$word]} ];then
map[$word]=1
else
let map[$word]++
fi
done
done < words.txt

for key in ${!map[@]}
do
echo $key ${map[$key]}
done
 题目的意思是统计一个文件中单词重复的次数,开始写法如L24,while循环结束后,map依然为空,后来才知道是使用了管道的缘故

 当启用管道时,会生成一个subshell,while循环的代码在subshell中执行,那么变量map也是在subshell中被修改,

 while循环结束后,回到主shell,map没有被修改,也就是说,两个map不是同一个map,while中修改的map是外层map的副本

 修改代码,将读取文件的格式改成L36,程序运行正常
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