您的位置:首页 > 编程语言 > Java开发

java通过模拟表单实现post跳转

2017-03-20 00:00 337 查看
今天在实现一个跳转功能时发现参数太长了,用redirect无法实现,想改成post提交参数。java自身的api貌似无法实现,最后查到可以用模拟一个表单提交参数的方式实现。

代码如下:

增加http请求工具类

import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;

/**
* Created by crimson.
*/
public class HttpClientUtil {
Map<String, String> parameter=new HashMap<>();
HttpServletResponse response;

public HttpClientUtil(HttpServletResponse response)
{
this.response=response;
}
public void setParameter(String key,String value)
{
this.parameter.put(key, value);
}
public void sendByPost(String url) throws IOException
{
this.response.setContentType("text/html");
PrintWriter out = this.response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE></TITLE></HEAD>");
out.println(" <BODY>");
out.println("<form name=\"submitForm\" action=\""+url+"\" method=\"post\">");
Iterator<String> it=this.parameter.keySet().iterator();
while(it.hasNext())
{
String key=it.next();
out.println("<input type=\"hidden\" name=\""+key+"\" value=\""+this.parameter.get(key)+"\"/>");
}
out.println("</from>");
out.println("<script>window.document.submitForm.submit();</script> ");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
}

调用处:

HttpClientUtil http=new HttpClientUtil (response);
http.setParameter("key", "value");
http.sendByPost(url);
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: