CodeForces - 58B Coins(水题。。大水题)

题目：

B. Coins

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

In Berland a money reform is being prepared. New coins are being introduced. After long economic calculations was decided that the most expensive coin should possess the denomination of exactly n Berland
dollars. Also the following restriction has been introduced for comfort: the denomination of each coin should be divisible by the denomination of any cheaper coin. It is known that among all the
possible variants the variant with the largest number of new coins will be chosen. Find this variant. Print in the order of decreasing of the coins' denominations.

Input

The first and only line contains an integer n (1 ≤ n ≤ 106)
which represents the denomination of the most expensive coin.

Output

Print the denominations of all the coins in the order of decreasing. The number of coins must be the largest possible (with the given denomination n of
the most expensive coin). Also, the denomination of every coin must be divisible by the denomination of any cheaper coin. Naturally, the denominations of all the coins should be different. If there are several solutins to that problem, print any of them.

Examples

input

10

output

10 5 1

input

4

output

4 2 1

input

3

output

3 1

思路：

我还能说什么。。。这么水的一个题我比赛竟然没写？思路就是。。暴力

代码1（c++）：

#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <string>
#include <iostream>
#include <stack>
#include <queue>
#include <vector>
#include <algorithm>
#define mem(a,b) memset(a,b,sizeof(a))
#define N (2000+20)
#define M 200010#define MOD (1000000000+7)
#define inf 0x3f3f3f3f
#define LL long long
using namespace std;
int main()
{
int n,i;
scanf("%d",&n);
for (i=n; i>0; i--)
if(n%i==0)
printf("%d ",n=i);

return 0;
}

代码2（python3）:
n=int(input())
for i in range(n,0,-1):
if n%i==0:
n=i
print(n)