九度OJ1094解题报告
2017-03-14 18:12
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时间限制:1 秒内存限制:32 兆特殊判题:否提交:1626解决:895
题目描述:
Finding all occurrences of a pattern in a text is a problem that arises frequently in text-editing programs.
Typically,the text is a document being edited,and the pattern searched for is a particular word supplied by the user.
We assume that the text is an array T[1..n] of length n and that the pattern is an array P[1..m] of length m<=n.We further assume that the elements of P and T are all alphabets(∑={a,b...,z}).The character arrays P and T are often called strings of characters.
We say that pattern P occurs with shift s in the text T if 0<=s<=n and T[s+1..s+m] = P[1..m](that is if T[s+j]=P[j],for 1<=j<=m).
If P occurs with shift s in T,then we call s a valid shift;otherwise,we calls a invalid shift.
Your task is to calculate the number of vald shifts for the given text T and p attern P.
输入:
For each case, there are two strings T and P on a line,separated by a single space.You may assume both the length of T and P will not exceed 10^6.
输出:
You should output a number on a separate line,which indicates the number of valid shifts for the given text T and pattern P.
样例输入:
abababab abab
样例输出:
3
源代码一:
#include <iostream>
#include <string>
#include <map>
using namespace std;
int main(){
string str,ch;
while(cin>>str>>ch){
int strlen=str.length(),chlen=ch.length();
int i,j,k,flag=1,count1=0;
for(i=0;i<strlen;i++){
j=0;
while(str[i+j]==ch[j]){
j++;
if(j==chlen) {
count1++;
break;
}
}
}
cout<<count1<<endl;
}
return 0;
}
源代码二:
#include <iostream>
#include <string>
#include <map>
using namespace std;
int main(){
string str,ch;
while(cin>>str>>ch){
int strlen=str.length(),chlen=ch.length();
int i,j,k,flag=1,count1=0;
for(i=0;i<strlen;i++){
j=0;
while(str[i+j]==ch[j]){
j++;
}
if(j>=chlen) {
count1++;
}
}
cout<<count1<<endl;
}
return 0;
}
/**************************************************************
Problem: 1094
User: kaoyandaren123
Language: C++
Result: Accepted
Time:130 ms
Memory:3052 kb
****************************************************************/
题目描述:
Finding all occurrences of a pattern in a text is a problem that arises frequently in text-editing programs.
Typically,the text is a document being edited,and the pattern searched for is a particular word supplied by the user.
We assume that the text is an array T[1..n] of length n and that the pattern is an array P[1..m] of length m<=n.We further assume that the elements of P and T are all alphabets(∑={a,b...,z}).The character arrays P and T are often called strings of characters.
We say that pattern P occurs with shift s in the text T if 0<=s<=n and T[s+1..s+m] = P[1..m](that is if T[s+j]=P[j],for 1<=j<=m).
If P occurs with shift s in T,then we call s a valid shift;otherwise,we calls a invalid shift.
Your task is to calculate the number of vald shifts for the given text T and p attern P.
输入:
For each case, there are two strings T and P on a line,separated by a single space.You may assume both the length of T and P will not exceed 10^6.
输出:
You should output a number on a separate line,which indicates the number of valid shifts for the given text T and pattern P.
样例输入:
abababab abab
样例输出:
3
源代码一:
#include <iostream>
#include <string>
#include <map>
using namespace std;
int main(){
string str,ch;
while(cin>>str>>ch){
int strlen=str.length(),chlen=ch.length();
int i,j,k,flag=1,count1=0;
for(i=0;i<strlen;i++){
j=0;
while(str[i+j]==ch[j]){
j++;
if(j==chlen) {
count1++;
break;
}
}
}
cout<<count1<<endl;
}
return 0;
}
源代码二:
#include <iostream>
#include <string>
#include <map>
using namespace std;
int main(){
string str,ch;
while(cin>>str>>ch){
int strlen=str.length(),chlen=ch.length();
int i,j,k,flag=1,count1=0;
for(i=0;i<strlen;i++){
j=0;
while(str[i+j]==ch[j]){
j++;
}
if(j>=chlen) {
count1++;
}
}
cout<<count1<<endl;
}
return 0;
}
/**************************************************************
Problem: 1094
User: kaoyandaren123
Language: C++
Result: Accepted
Time:130 ms
Memory:3052 kb
****************************************************************/
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