Problem H: 平面上的点和线——Point类、Line类 (IV)

Problem H: 平面上的点和线——Point类、Line类 (IV)

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 3106  Solved: 1981

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Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。

根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。

接口描述：
Point::show()方法：按格式输出Point对象。
Line::show()方法：按格式输出Line对象。

Input

输入的第一行为N，表示后面有N行测试样例。

每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。

Output

输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。

C语言的输入输出被禁用。

Sample Input

40,0 1,11,1 2,32,3 4,50,1 1,0

Sample Output

Point : (1, -2) is created.Point : (2, -1) is created.Point : (0, 0) is created.Point : (0, 0)Point : (0, 0) is created.Point : (0, 0) is created.Line
: (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line
: (0, 0) to (0, 0) is created.=========================Line : (0, 0) to (1, 1)=========================Line : (1, 1) to (2, 3)=========================Line : (2, 3) to (4, 5)=========================Line : (0, 1) to (1, 0)=========================Point : (1,
-2) is copied.Point : (2, -1) is copied.Line : (1, -2) to (2, -1) is created.Point : (1, -2) is copied.Point : (0, 0) is copied.Line : (1, -2) to (0, 0) is created.Point : (2, -1) is copied.Point : (0, 0) is copied.Line : (2, -1) to (0, 0) is created.Point
: (0, 0) is copied.Point : (2, -1) is copied.Line : (0, 0) to (2, -1) is created.Line : (1, -2) to (2, -1)Line : (1, -2) to (0, 0)Line : (2, -1) to (0, 0)Line : (0, 0) to (2, -1)Line : (0, 0) to (2, -1) is erased.Point : (2, -1) is erased.Point : (0, 0) is
erased.Line : (2, -1) to (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Line : (1, -2) to (0, 0) is erased.Point : (0, 0) is erased.Point : (1, -2) is erased.Line : (1, -2) to (2, -1) is erased.Point : (2, -1) is erased.Point : (1, -2)
is erased.Line : (0, 1) to (1, 0) is erased.Point : (1, 0) is erased.Point : (0, 1) is erased.Line : (2, 3) to (4, 5) is erased.Point : (4, 5) is erased.Point : (2, 3) is erased.Line : (1, 1) to (2, 3) is erased.Point : (2, 3) is erased.Point : (1, 1) is erased.Line
: (0, 0) to (1, 1) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.

HINT

Append Code

append.cc,

#include <iostream>
#include <iomanip>
using namespace std;
class Point
{
friend class Line;
private:
double x;
double y;
public:
Point():x(0),y(0){cout<<"Point : ("<<x<<", "<<y<<") is created."<<endl;}
Point(double xx,double yy):x(xx),y(yy)
{
cout<<"Point : ("<<x<<", "<<y<<") is created."<<endl;
}
Point(const Point &p):x(p.x),y(p.y)
{
cout<<"Point : ("<<x<<", "<<y<<") is copied."<<endl;
}
~Point()
{
cout<<"Point : ("<<x<<", "<<y<<") is erased."<<endl;
}
void show()
{
cout<<"Point : ("<<x<<", "<<y<<")"<<endl;
}
};
class Line
{
friend class Point;
private:
Point p_1,p_2;
public:
Line():p_1(0,0),p_2(0,0)
{
cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is created."<<endl;
}
Line(Point &m,Point &n):p_1(m),p_2(n)
{
cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is created."<<endl;
}
Line(double a,double b,double c,double d):p_1(a,b),p_2(c,d)
{
cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is created."<<endl;
}
~Line()
{
cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<") is erased."<<endl;
}
void show()
{
cout<<"Line : ("<<p_1.x<<", "<<p_1.y<<") to ("<<p_2.x<<", "<<p_2.y<<")"<<endl;
}
void SetLine(double a,double b,double c,double d)
{
p_1.x = a;
p_1.y = b;
p_2.x = c;
p_2.y = d;
}
};
int main()
{
char c;
int num, i;
double x1, x2, y1, y2;
Point p(1, -2), q(2, -1), t;
t.show();
std::cin>>num;
Line line[num];
for(i = 0; i < num; i++)
{
std::cout<<"=========================\n";
std::cin>>x1>>c>>y1>>x2>>c>>y2;
line[i].SetLine(x1, y1, x2, y2);
line[i].show();
}
std::cout<<"=========================\n";
Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);
l1.show();
l2.show();
l3.show();
l4.show();
}