动态规划系列【2】最长递增子序列LIS
2017-03-03 21:03
393 查看
Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than one LIS combination, it is only necessary for you to return the length. Your algorithm should run in O(n2) complexity. Follow up: Could you improve it to O(n log n) time complexity? Credits: Special thanks to @pbrother for adding this problem and creating all test cases. Subscribe to see which companies asked this question.题意:无需多说。主要是这玩意有基础版O(n^2)和增强版O(nlogn)
public class Solution { public int lengthOfLIS(int[] nums) { int length=nums.length; if(length==0)return 0; int max=1; int[] d=new int[length]; for(int i=1;i<length;i++){ d[i]=1; for(int j=0;j<i;j++){ if(nums[j]<nums[i]) d[i]=Math.min(d[i],d[j]=1); } max=Math.max(d[i],max); } return max; } }PS:思路参加http://www.hawstein.com/posts/dp-novice-to-advanced.html
public class AscentSequence { public int findLongest(int[] A, int n) { // write code here int[] dp=new int ; int[] ends=new int ; ends[0]=A[0]; dp[0]=1; int max=1; int r=0,right=0,l=0,m=0; for(int i=1;i<n;i++){ l=0; r=right; while(l<=r){ m=(l+r)/2; if(A[i]>ends[m]){ l=m+1; }else{ r=m-1; } } //没明白 right=Math.max(l,right); ends[l]=A[i]; dp[i]=l+1; max=Math.max(dp[i],max); } return max; } }用二分查找、辅助数组。
最后是打印出来最长递增子序列
public static int[] getLIS(int[] arr,int[] dp){ int maxlen=0; int index=0; for(int i=0;i<dp.length;i++){ if(dp[i]>maxlen){ maxlen=dp[i]; index=i; } } System.out.println(index+""+maxlen); int[] list=new int[maxlen]; list[--maxlen]=arr[index]; for(int j=index;j>=0;j--){ if(arr[j]<arr[index] && dp[j]+1==dp[index]){ list[--maxlen]=arr[j]; index=j; } } return list; }PS:首先找到dp中最大值及其索引index。然后去数组arr[index]中从右往左遍历。找到第一个小于arr[index]且dp[]+1==dp[index]的值作为倒数第二个数。一次往后重复此过程。
相关文章推荐
- 动态规划系列之最长递增子序列问题解答
- 动态规划4:LIS最长递增子序列问题
- HDU - 1257 最少拦截系统(LIS最长递增子序列)
- 【动态规划】最长上升子序列(LIS)
- 【动态规划】 最长递增子序列
- DP之最长递增子序列LIS
- 九度OJ 1131 合唱队形 -- 动态规划(最长递增子序列)
- 动态规划-求最长递增子序列
- 动态规划--最长递增子序列
- 动态规划——最长递增子序列
- 【动态规划】拦截导弹_dilworth定理_最长递增子序列
- HDU Monkey and Banana 1069 dp 动态规划 最长递增子序列
- LIS(最长递增子序列) Zigzag
- LIS(最长递增子序列) Zigzag
- (DP6.1.4.1)UVA 111 History Grading(最长递增子序列LIS 的LCS 解法)
- 求数组中最长递增子序列—动态规划入门(编程之美)
- 最长递增子序列LIS
- [置顶] 【动态规划】最长递增子序列
- 动态规划 最长递增子序列
- 最长递增子序列LIS