PAT甲级1061. Dating (20)

Sherlock Holmes received a note with some strange strings: “Let’s date! 3485djDkxh4hhGE 2984akDfkkkkggEdsb s&hgsfdk d&Hyscvnm”. It took him only a minute to figure out that those strange strings are actually referring to the coded time “Thursday 14:04” – since the first common capital English letter (case sensitive) shared by the first two strings is the 4th capital letter ‘D’, representing the 4th day in a week; the second common character is the 5th capital letter ‘E’, representing the 14th hour (hence the hours from 0 to 23 in a day are represented by the numbers from 0 to 9 and the capital letters from A to N, respectively); and the English letter shared by the last two strings is ‘s’ at the 4th position, representing the 4th minute. Now given two pairs of strings, you are supposed to help Sherlock decode the dating time.

Input Specification:

Each input file contains one test case. Each case gives 4 non-empty strings of no more than 60 characters without white space in 4 lines.

Output Specification:

For each test case, print the decoded time in one line, in the format “DAY HH:MM”, where “DAY” is a 3-character abbreviation for the days in a week – that is, “MON” for Monday, “TUE” for Tuesday, “WED” for Wednesday, “THU” for Thursday, “FRI” for Friday, “SAT” for Saturday, and “SUN” for Sunday. It is guaranteed that the result is unique for each case.

Sample Input:

3485djDkxh4hhGE

2984akDfkkkkggEdsb

s&hgsfdk

d&Hyscvnm

Sample Output:

THU 14:04

day in the week:前两个字符串的第一个位置相同的大写字母

hour: 前两个字符串第二个位置相同的字符

minute: 后两个字符串第一个位置相同的英文字母的位置

以上都要注意范围

#include <iostream>
using namespace std;
#include <string>

const char* week[]={"MON","TUE","WED","THU","FRI","SAT","SUN"};

int main(){
string S1,S2,S3,S4;
cin>>S1>>S2>>S3>>S4;

//get the day in the week
char Day;
int i=0,j=0;
for(i=0;i<S1.length()&&i<S2.length();i++){
if(S1[i]==S2[i]&&(S1[i]>='A'&&S1[i]<='G')) { //注意范围
Day=S1[i];
break;
}
}
//cout<<"i="<<i<<endl;
//get Hour
char Hour;
for(j=i+1;j<S1.length()&&j<S2.length();j++){
if(S1[j]==S2[j]&&((S1[j]>='A'&&S1[j]<='N')||(S1[j]>='0'&&S1[j]
4000
<='9'))) { //注意范围
Hour=S1[j];
break;
}
}
//  cout<<"j="<<j<<endl;

//get Minute
int minute;
for(int i=0;i<S3.length()&&i<S4.length();i++){
if((S3[i]==S4[i])&&((S3[i]>='A'&&S3[i]<='Z')||(S3[i]>='a'&&S3[i]<='z'))){
minute=i;
break;
}
}

cout<<week[Day-'A']<<" ";
if(Hour>='0'&&Hour<='9') cout<<0<<Hour<<":";
else cout<<10+Hour-'A'<<":";
if(minute<10) cout<<"0";
cout<<minute;

return 0;
}