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Codeforces Round #402 (Div. 1) 题解(待续)

2017-02-27 15:59 309 查看

A String Game

#include<bits/stdc++.h>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define ForkD(i,k,n) for(int i=n;i>=k;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=Pre[x];p;p=Next[p])
#define Forpiter(x) for(int &p=iter[x];p;p=Next[p])
#define Lson (o<<1)
#define Rson ((o<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (2139062143)
#define F (1000000007)
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define vi vector<int>
#define pi pair<int,int>
#define SI(a) ((a).size())
#define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans);
#define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a
<<endl;
#define PRi2D(a,n,m) For(i,n) { \
For(j,m-1) cout<<a[i][j]<<' ';\
cout<<a[i][m]<<endl; \
}
#pragma comment(linker, "/STACK:102400000,102400000")
#define ALL(x) (x).begin(),(x).end()
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
int x=0,f=1; char ch=getchar();
while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
return x*f;
}
#define MAXN (212345)
char s[MAXN],t[MAXN];
int a[MAXN];
int n,l;
char s2[MAXN];
bool check(int m) {
int cnt=0;
For(i,n) if (a[i]>m) s2[cnt++]=s[i];
int p=0;
Rep(i,cnt) {
if (s2[i]==t[p]) ++p;
if (p==l) return 1;
}return 0;
}
int main()
{
//  freopen("A.in","r",stdin);
//  freopen(".out","w",stdout);

cin>>(s+1)>>t;
n=strlen(s+1),l=strlen(t);
For(i,n) {
int p=read();
a[p]=i;
}
int l=0,r=n,ans=0;
while(l<=r) {
int m=(l+r)/2;
if (check(m)) ans=m,l=m+1;else r=m-1;
}
cout<<ans<<endl;
return 0;
}


B Bitwise Formula

这不是NOI原题

#include<bits/stdc++.h>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define ForkD(i,k,n) for(int i=n;i>=k;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=Pre[x];p;p=Next[p])
#define Forpiter(x) for(int &p=iter[x];p;p=Next[p])
#define Lson (o<<1)
#define Rson ((o<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (2139062143)
#define F (1000000007)
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define vi vector<int>
#define pi pair<int,int>
#define SI(a) ((a).size())
#define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans);
#define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a
<<endl;
#define PRi2D(a,n,m) For(i,n) { \
For(j,m-1) cout<<a[i][j]<<' ';\
cout<<a[i][m]<<endl; \
}
#pragma comment(linker, "/STACK:102400000,102400000")
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
int x=0,f=1; char ch=getchar();
while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
return x*f;
}
int n,m;
#define MAXN (5123)
char s[5123];
map<string,string> h,h2;
stringstream ss;
string s0,s1;
bool b;
string get(string s) {
if (s[0]=='0'||s[0]=='1') return s;
if (s[0]=='?') {
if (b==0) return s0;
return s1;

}
if (b==0) return h[s];
return h2[s];
}
string get(string s,string op,string s2) {
s=get(s),s2=get(s2);
if (op=="XOR") {
Rep(i,m) s[i]='0'+((s[i]-'0')^(s2[i]-'0'));
}
else if (op=="AND") {
Rep(i,m) s[i]='0'+((s[i]-'0')&(s2[i]-'0'));
}
else {
Rep(i,m) s[i]='0'+((s[i]-'0')|(s2[i]-'0'));
}return s;
}
int f[MAXN][2]={};
int main()
{
//  freopen("B.in","r",stdin);
//  freopen(".out","w",stdout);

cin>>n>>m;
s0=string(m,'0');
s1=string(m,'1');
//  cout<<s0<<endl;
cin.getline(s,5120);
For(i,n) {
cin.getline(s,5120);
//      cout<<s<<endl;
ss<<s;
string s1,p,s2,s3,s4;
bool fl=0;
ss>>s1>>p>>s2;
fl= (ss>>s3>>s4);
b=0;
if (!fl) {
h[s1]=get(s2);
} else {
h[s1]=get(s2,s3,s4);
}
b=1;
if (!fl) {
h2[s1]=get(s2);
} else {
h2[s1]=get(s2,s3,s4);
}

ss.clear();
//      cout<<h[s1]<<endl;
//      cout<<h2[s1]<<endl;

p=h[s1];
Rep(i,m) if (p[i]=='1') ++f[i][0];
p=h2[s1];
Rep(i,m) if (p[i]=='1') ++f[i][1];

}

Rep(i,m) {
if (f[i][0]<=f[i][1]) putchar('0');
else putchar('1');
}
cout<<endl;
Rep(i,m) {
if (f[i][0]>=f[i][1]) putchar('0');
else putchar('1');
}
cout<<endl;

return 0;
}


C Peterson Polyglot

直接启发式合并字典树暴力计数(这怎么能是正解系列)

#include<bits/stdc++.h>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define ForkD(i,k,n) for(int i=n;i>=k;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=Pre[x];p;p=Next[p])
#define Forpiter(x) for(int &p=iter[x];p;p=Next[p])
#define Lson (o<<1)
#define Rson ((o<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (2139062143)
#define F (1000000007)
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define vi vector<int>
#define pi pair<int,int>
#define SI(a) ((a).size())
#define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans);
#define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a
<<endl;
#define PRi2D(a,n,m) For(i,n) { \
For(j,m-1) cout<<a[i][j]<<' ';\
cout<<a[i][m]<<endl; \
}
#pragma comment(linker, "/STACK:102400000,102400000")
#define ALL(x) (x).begin(),(x).end()
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
int x=0,f=1; char ch=getchar();
while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
return x*f;
}
#define MAXN (912345)
struct node {
int ch[26];
}t[MAXN];
int n,cnt,c[MAXN]={};
int merge(int x,int y,int d) {
if (!x||!y) return x+y;
c[d]++;
int p=++cnt;
Rep(i,26) t[p].ch[i]=merge(t[x].ch[i],t[y].ch[i],d);
return p;
}
void dfs(int u,int d) {
Rep(i,26) if (t[u].ch[i])
dfs(t[u].ch[i],d+1);
int rt = 0;
Rep(i,26) rt=merge(rt,t[u].ch[i],d);
if (rt) c[d]++;
}
int main()
{
//  freopen("C.in","r",stdin);
//  freopen(".out","w",stdout);
n=read();
For(i,n-1) {
int u,v; char c;
scanf("%d %d %c",&u,&v,&c);
t[u].ch[c-'a']=v;
}
cnt=n;
dfs(1,1);
cout<<n-*max_element(c,c+n)<<endl;
cout<<(max_element(c,c+n)-c)<<endl;
return 0;
}
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