Codeforces Round #402 (Div. 1) 题解(待续)
2017-02-27 15:59
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A String Game
#include<bits/stdc++.h> using namespace std; #define For(i,n) for(int i=1;i<=n;i++) #define Fork(i,k,n) for(int i=k;i<=n;i++) #define Rep(i,n) for(int i=0;i<n;i++) #define ForD(i,n) for(int i=n;i;i--) #define ForkD(i,k,n) for(int i=n;i>=k;i--) #define RepD(i,n) for(int i=n;i>=0;i--) #define Forp(x) for(int p=Pre[x];p;p=Next[p]) #define Forpiter(x) for(int &p=iter[x];p;p=Next[p]) #define Lson (o<<1) #define Rson ((o<<1)+1) #define MEM(a) memset(a,0,sizeof(a)); #define MEMI(a) memset(a,127,sizeof(a)); #define MEMi(a) memset(a,128,sizeof(a)); #define INF (2139062143) #define F (1000000007) #define pb push_back #define mp make_pair #define fi first #define se second #define vi vector<int> #define pi pair<int,int> #define SI(a) ((a).size()) #define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans); #define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a <<endl; #define PRi2D(a,n,m) For(i,n) { \ For(j,m-1) cout<<a[i][j]<<' ';\ cout<<a[i][m]<<endl; \ } #pragma comment(linker, "/STACK:102400000,102400000") #define ALL(x) (x).begin(),(x).end() typedef long long ll; typedef long double ld; typedef unsigned long long ull; ll mul(ll a,ll b){return (a*b)%F;} ll add(ll a,ll b){return (a+b)%F;} ll sub(ll a,ll b){return ((a-b)%F+F)%F;} void upd(ll &a,ll b){a=(a%F+b%F)%F;} int read() { int x=0,f=1; char ch=getchar(); while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();} while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();} return x*f; } #define MAXN (212345) char s[MAXN],t[MAXN]; int a[MAXN]; int n,l; char s2[MAXN]; bool check(int m) { int cnt=0; For(i,n) if (a[i]>m) s2[cnt++]=s[i]; int p=0; Rep(i,cnt) { if (s2[i]==t[p]) ++p; if (p==l) return 1; }return 0; } int main() { // freopen("A.in","r",stdin); // freopen(".out","w",stdout); cin>>(s+1)>>t; n=strlen(s+1),l=strlen(t); For(i,n) { int p=read(); a[p]=i; } int l=0,r=n,ans=0; while(l<=r) { int m=(l+r)/2; if (check(m)) ans=m,l=m+1;else r=m-1; } cout<<ans<<endl; return 0; }
B Bitwise Formula
这不是NOI原题#include<bits/stdc++.h> using namespace std; #define For(i,n) for(int i=1;i<=n;i++) #define Fork(i,k,n) for(int i=k;i<=n;i++) #define Rep(i,n) for(int i=0;i<n;i++) #define ForD(i,n) for(int i=n;i;i--) #define ForkD(i,k,n) for(int i=n;i>=k;i--) #define RepD(i,n) for(int i=n;i>=0;i--) #define Forp(x) for(int p=Pre[x];p;p=Next[p]) #define Forpiter(x) for(int &p=iter[x];p;p=Next[p]) #define Lson (o<<1) #define Rson ((o<<1)+1) #define MEM(a) memset(a,0,sizeof(a)); #define MEMI(a) memset(a,127,sizeof(a)); #define MEMi(a) memset(a,128,sizeof(a)); #define INF (2139062143) #define F (1000000007) #define pb push_back #define mp make_pair #define fi first #define se second #define vi vector<int> #define pi pair<int,int> #define SI(a) ((a).size()) #define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans); #define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a <<endl; #define PRi2D(a,n,m) For(i,n) { \ For(j,m-1) cout<<a[i][j]<<' ';\ cout<<a[i][m]<<endl; \ } #pragma comment(linker, "/STACK:102400000,102400000") typedef long long ll; typedef long double ld; typedef unsigned long long ull; ll mul(ll a,ll b){return (a*b)%F;} ll add(ll a,ll b){return (a+b)%F;} ll sub(ll a,ll b){return ((a-b)%F+F)%F;} void upd(ll &a,ll b){a=(a%F+b%F)%F;} int read() { int x=0,f=1; char ch=getchar(); while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();} while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();} return x*f; } int n,m; #define MAXN (5123) char s[5123]; map<string,string> h,h2; stringstream ss; string s0,s1; bool b; string get(string s) { if (s[0]=='0'||s[0]=='1') return s; if (s[0]=='?') { if (b==0) return s0; return s1; } if (b==0) return h[s]; return h2[s]; } string get(string s,string op,string s2) { s=get(s),s2=get(s2); if (op=="XOR") { Rep(i,m) s[i]='0'+((s[i]-'0')^(s2[i]-'0')); } else if (op=="AND") { Rep(i,m) s[i]='0'+((s[i]-'0')&(s2[i]-'0')); } else { Rep(i,m) s[i]='0'+((s[i]-'0')|(s2[i]-'0')); }return s; } int f[MAXN][2]={}; int main() { // freopen("B.in","r",stdin); // freopen(".out","w",stdout); cin>>n>>m; s0=string(m,'0'); s1=string(m,'1'); // cout<<s0<<endl; cin.getline(s,5120); For(i,n) { cin.getline(s,5120); // cout<<s<<endl; ss<<s; string s1,p,s2,s3,s4; bool fl=0; ss>>s1>>p>>s2; fl= (ss>>s3>>s4); b=0; if (!fl) { h[s1]=get(s2); } else { h[s1]=get(s2,s3,s4); } b=1; if (!fl) { h2[s1]=get(s2); } else { h2[s1]=get(s2,s3,s4); } ss.clear(); // cout<<h[s1]<<endl; // cout<<h2[s1]<<endl; p=h[s1]; Rep(i,m) if (p[i]=='1') ++f[i][0]; p=h2[s1]; Rep(i,m) if (p[i]=='1') ++f[i][1]; } Rep(i,m) { if (f[i][0]<=f[i][1]) putchar('0'); else putchar('1'); } cout<<endl; Rep(i,m) { if (f[i][0]>=f[i][1]) putchar('0'); else putchar('1'); } cout<<endl; return 0; }
C Peterson Polyglot
直接启发式合并字典树暴力计数(这怎么能是正解系列)#include<bits/stdc++.h> using namespace std; #define For(i,n) for(int i=1;i<=n;i++) #define Fork(i,k,n) for(int i=k;i<=n;i++) #define Rep(i,n) for(int i=0;i<n;i++) #define ForD(i,n) for(int i=n;i;i--) #define ForkD(i,k,n) for(int i=n;i>=k;i--) #define RepD(i,n) for(int i=n;i>=0;i--) #define Forp(x) for(int p=Pre[x];p;p=Next[p]) #define Forpiter(x) for(int &p=iter[x];p;p=Next[p]) #define Lson (o<<1) #define Rson ((o<<1)+1) #define MEM(a) memset(a,0,sizeof(a)); #define MEMI(a) memset(a,127,sizeof(a)); #define MEMi(a) memset(a,128,sizeof(a)); #define INF (2139062143) #define F (1000000007) #define pb push_back #define mp make_pair #define fi first #define se second #define vi vector<int> #define pi pair<int,int> #define SI(a) ((a).size()) #define Pr(kcase,ans) printf("Case #%d: %I64d\n",kcase,ans); #define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a <<endl; #define PRi2D(a,n,m) For(i,n) { \ For(j,m-1) cout<<a[i][j]<<' ';\ cout<<a[i][m]<<endl; \ } #pragma comment(linker, "/STACK:102400000,102400000") #define ALL(x) (x).begin(),(x).end() typedef long long ll; typedef long double ld; typedef unsigned long long ull; ll mul(ll a,ll b){return (a*b)%F;} ll add(ll a,ll b){return (a+b)%F;} ll sub(ll a,ll b){return ((a-b)%F+F)%F;} void upd(ll &a,ll b){a=(a%F+b%F)%F;} int read() { int x=0,f=1; char ch=getchar(); while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();} while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();} return x*f; } #define MAXN (912345) struct node { int ch[26]; }t[MAXN]; int n,cnt,c[MAXN]={}; int merge(int x,int y,int d) { if (!x||!y) return x+y; c[d]++; int p=++cnt; Rep(i,26) t[p].ch[i]=merge(t[x].ch[i],t[y].ch[i],d); return p; } void dfs(int u,int d) { Rep(i,26) if (t[u].ch[i]) dfs(t[u].ch[i],d+1); int rt = 0; Rep(i,26) rt=merge(rt,t[u].ch[i],d); if (rt) c[d]++; } int main() { // freopen("C.in","r",stdin); // freopen(".out","w",stdout); n=read(); For(i,n-1) { int u,v; char c; scanf("%d %d %c",&u,&v,&c); t[u].ch[c-'a']=v; } cnt=n; dfs(1,1); cout<<n-*max_element(c,c+n)<<endl; cout<<(max_element(c,c+n)-c)<<endl; return 0; }
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