简单枚举类型——植物与颜色

简单枚举类型——植物与颜色

Time Limit: 1000MS
Memory Limit: 65536KB
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Problem Description

 请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color，根据输入的颜色名称，输出以下六种植物花朵的颜色：
Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中，例如输入purple，请输出I don't know about the color purple.
 

Input

 输入数据有多行，每行有一个字符串代表颜色名称，颜色名称最多30个字符，直到文件结束为止。

Output

 输出对应颜色的植物名称，例如：Bluebells are blue. 如果输入的颜色名称不在枚举类型color中，例如purple, 请输出I don't know about the color purple.
 

Example Input

blue
yellow
purple

Example Output

Bluebells are blue.
Sunflower are yellow.
I don't know about the color purple.

Hint

请用枚举类型实现。

#include<stdio.h>
#include<string.h>
enum
{
red, orange, yellow, green, blue, violet,no
} w;
int main()
{
char a[31];
while(gets(a))
{
if(strcmp(a,"red")==0)
{
w=red;
}
else if(strcmp(a,"orange")==0)
{
w=orange;
}
else if(strcmp(a,"yellow")==0)
{
w=yellow;
}
else if(strcmp(a,"green")==0)
{
w=green;
}
else if(strcmp(a,"blue")==0)
{
w=blue;
}
else if(strcmp(a,"violet")==0)
{
w=violet;
}
else
{
w=no;
}
switch(w)
{
case red:
printf("Rose are red.\n");
break;
case yellow:
printf("Sunflower are yellow.\n");
break;
case orange:
printf("Poppies are orange.\n");
break;
case blue:
printf("Bluebells are blue.\n");
break;
case green:
printf("Grass are green.\n");
break;
case violet:
printf("Violets are violet.\n");
break;
case no:
printf("I don't know about the color %s.\n",a);
break;
}
}
return 0;
}