Android开发——获取并生成唯一识别码

//获得独一无二的Psuedo ID
public static String getUniquePsuedoID() {
String serial = null;

String m_szDevIDShort = "35" +
Build.BOARD.length()%10+ Build.BRAND.length()%10 +

Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +

Build.DISPLAY.length()%10 + Build.HOST.length()%10 +

Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +

Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +

Build.TAGS.length()%10 + Build.TYPE.length()%10 +

Build.USER.length()%10 ; //13 位

try {
serial = android.os.Build.class.getField("SERIAL").get(null).toString();
//API>=9 使用serial号
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
} catch (Exception exception) {
//serial需要一个初始化
serial = "serial"; // 随便一个初始化
}
//使用硬件信息拼凑出来的15位号码
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();

<uses-permission android.permission.READ_PHONE_STATE/>

public static String getAPPID(){
final TelephonyManager tm = (TelephonyManager) MyApplication.getContext().getSystemService(Context.TELEPHONY_SERVICE);
final String tmDevice, tmSerial, androidId;
tmDevice = "" + tm.getDeviceId();
tmSerial = "" + tm.getSimSerialNumber();
androidId = "" + android.provider.Settings.Secure.getString(MyApplication.getContext().getContentResolver(), android.provider.Settings.Secure.ANDROID_ID);

UUID deviceUuid = new UUID(androidId.hashCode(), ((long)tmDevice.hashCode() << 32) | tmSerial.hashCode());
return deviceUuid.toString();

}