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LeetCode:Single Number

2017-02-23 11:39 357 查看
Given an array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

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class Solution {
public:
int singleNumber(vector<int>& nums) {
int result = 0;
for(int i=0;i<nums.size();++i)
{
result = result^nums[i];
}
return result;
}
};
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标签:  leetcode