LeetCode_504. Base 7
2017-02-18 13:06
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504. Base 7
Given an integer, return its base 7 string representation.Example 1:
Input: 100 Output: "202"
Example 2:
Input: -7 Output: "-10"
Note: The input wil be in range of [-1e7, 1e7].
解题思路:
题意:将十进制数字转换成7进制,且以字符串形式返回。若数字为负数,则将其绝对值转换后再添加符号。
class Solution { public: string convertToBase7(int num) { if (num==0) return "0"; bool flag = (num>0)?true:false; num = (num>0)?num:num*(-1); string res; int tmp; while (num!=0) { tmp = num%7; num /= 7; res = to_string(tmp)+res; } if (!flag) res = string(1, '-')+res; return res; } };
本题笔记:
此题的思路很简单,关键在于字符串赋值与连接的熟练使用。
1. 字符串初始化
// format 1: string s(n, 'c') std::string s1(10, 'a'); // format 2: std::string s("value");
2.字符串的连接
s = s1+s2;
3.to_string: convert numerical value to string
//string to_string (int value); std::to_string(10);
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