三道acm基础题 CSU-1000.1001.1002
2017-02-13 10:26
253 查看
1000: A+B (I)
Time Limit: 1 Sec Memory Limit:128 MB
Submit: 6295 Solved: 1753
[Submit][Status]
Description
Your task is to Calculate a + b.Input
Input contains multiple test cases. Each test case consists of a pair of integers a and b(0<=a,b<=20), separated by a space, one pair of integers per line.Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.Sample Input
1 1
Sample Output
2
HINT
Source
中南大学第五届大学生程序设计竞赛-热身赛[Submit][Status]
最基础的输入输出
#include<stdio.h>
using namespace std;
int main()
{
int a,b;
while(~scanf("%d%d",&a,&b))
{
printf("%d\n",a+b);
}
return 0;
}
1001: A+B (II)
Time Limit: 1 Sec Memory Limit:128 MB
Submit: 4111 Solved: 1354
[Submit][Status]
Description
Your task is to Calculate a + b.Input
There are multiple test cases. Each test case contains only one line. Each line consists of a pair of real number a and b(0<=a,b<=1000000), separated by a space.Output
For each case, output the answer in one line rounded to 4 digits after the decimal point.
For each case, output the answer in one line rounded to 4 digits after the decimal point.
Sample Input
1 5 10 20 0.1 1.5
Sample Output
6.0000 30.0000 1.6000
HINT
Source
中南大学第五届大学生程序设计竞赛-热身赛[Submit][Status]
[align=left]
[/align]
#include<stdio.h> using namespace std; int main(){ double a,b; while(~scanf("%lf %lf",&a,&b)) { printf("%.4f\n",a+b); } return 0; }
1002: A+B (III)
Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 3136 Solved: 1109
[Submit][Status]
Description
Your task is to Calculate a + b.Input
There are multiple test cases. Each test case contains only one line. Each line consists of a pair of integers a and b(1=< a,b <=1016), separated by a space. Input is followed by a single line with a = 0, b = 0, which should not be processed.Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.Sample Input
1 510 2010000000000000000 100000000000000000 0
Sample Output
63020000000000000000
HINT
Source
中南大学第五届大学生程序设计竞赛-热身赛[Submit][Status]
#include<stdio.h> #include<iostream> using namespace std; int main(){ long long a,b; while(~scanf("%lld%lld",&a,&b)) { if(a!=0&&b!=0) printf("%llu\n",a+b); } return 0; }
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