PAT BASIC 1021 个位数统计
2017-02-11 14:27
375 查看
思路:
这是一个简单的模拟题,没什么要注意的。代码:
#include<iostream> #include<string> using namespace std; int num[10] = { 0 }; string str; int main() { int len, i; cin >> str; len = str.size(); for (i = 0; i < len; i++) num[str[i] - '0']++; for (i = 0; i < 10; i++) if (num[i]) cout << i << ":" << num[i] << "\n"; //while (1) //{ //} return 0; }
相关文章推荐
- PAT (Basic Level) Practise (中文)1021. 个位数统计 (15)
- PAT(basic level) 1021 个位数统计(15)
- PAT BASIC LEVEL 1021. 个位数统计 (15)
- Pat(Basic Level)Practice--1021(个位数统计)
- PAT1021 BASIC:个位数统计 (15)
- PAT (Basic Level) Practise:1021. 个位数统计
- PAT Basic Level 1021. 个位数统计 (15)
- PAT (Basic Level)1021. 个位数统计
- PAT (Basic Level) Practise (中文)1021. 个位数统计 (15) C语言
- PAT Basic 1021. 个位数统计 (15)(C语言实现)
- PAT (Basic Level) Practise (中文)-1021. 个位数统计 (15)
- PAT (Basic Level) Practise (中文)1021. 个位数统计 (15)
- PAT (Basic Level) Practise (中文) 1021. 个位数统计 (15)
- PAT (Basic Level) Practise (中文)1021. 个位数统计 (15)
- PAT (Basic Level) Practise (中文)- 1021. 个位数统计 (15)
- PAT Basic Level 1021. 个位数统计(15)
- PAT(Basic Level)_1021_个位数统计
- PAT乙级 1021. 个位数统计 (15)
- PAT 乙级练习题1021. 个位数统计 (15)
- pat乙1021. 个位数统计 (15)