346. Moving Average from Data Stream
2017-02-11 09:15
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Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window.
For example,
一道设计题,限制了Queue的长度,可以加一个判断,如果Queue大于了size,就弹出第一个数,求剩下数和当前数的平均;如果没超过size,累加求平均。代码如下:
For example,
MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5) = (10 + 3 + 5) / 3
一道设计题,限制了Queue的长度,可以加一个判断,如果Queue大于了size,就弹出第一个数,求剩下数和当前数的平均;如果没超过size,累加求平均。代码如下:
public class MovingAverage { private int size = 0; private int count = 0; private Queue<Integer> queue = new LinkedList<Integer>(); private double average = 0; /** Initialize your data structure here.*/ public MovingAverage(int size) { this.size = size; } public double next(int val) { if (queue.size() >= size) { average = (average * size - queue.poll() + val) / size; queue.offer(val); } else { average = (average * queue.size() + val) / (queue.size() + 1); queue.offer(val); } return average; } } /** * Your MovingAverage object will be instantiated and called as such: * MovingAverage obj = new MovingAverage(size); * double param_1 = obj.next(val); */
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