from表单使用ajax异步提交

//js代码

function saveReport() {

    var getName=$("#getName").val();

    $.ajax({

        type: "POST",

        url: ,

        data : {name:getName},

        success: function(msg) {

            alert("提交成功");

        }

    });

    return false;

}   

//jsp代码

<form i  onsubmit="return saveReport();" >  

          <input type="text" class="input w50"  id="getName" value="" name="name"  />

          <button class="button bg-main icon-check-square-o"  type="submit"  >提交</button>

    </form>