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opencv使用-HoughLinesP and HoughLines

2017-02-09 21:24 295 查看
图像名称:“you_test.png”

推荐霍夫变换源码详细讲解:http://blog.csdn.net/zhaocj/article/details/40047397

#include "opencv2/imgcodecs.hpp"

#include "opencv2/highgui.hpp"

#include "opencv2/imgproc.hpp"

#include <iostream>

using namespace cv;

using namespace std;

static void help()

{

cout << "\nThis program demonstrates line finding with the Hough transform.\n"

"Usage:\n"

"./houghlines <image_name>, Default is ./you_test.png\n" << endl;

}

int main(int argc, char** argv)

{

cv::CommandLineParser parser(argc, argv,

"{help h||}{@image|./you_test.png|}"

);

if (parser.has("help"))

{

help();

return 0;

}

string filename = parser.get<string>("@image");

if (filename.empty())

{

help();

cout << "no image_name provided" << endl;

return -1;

}

Mat src = imread(filename, 0);

if(src.empty())

{

help();

cout << "can not open " << filename << endl;

return -1;

}

Mat dst, cdst;

Canny(src, dst, 50, 200, 3);

cvtColor(dst, cdst, COLOR_GRAY2BGR);

#if 0

vector<Vec2f> lines;

HoughLines(dst, lines, 1, CV_PI/180, 100, 0, 0 );

for( size_t i = 0; i < lines.size(); i++ )

{

float rho = lines[i][0], theta = lines[i][1];

Point pt1, pt2;

double a = cos(theta), b = sin(theta);

double x0 = a*rho, y0 = b*rho;

pt1.x = cvRound(x0 + 1000*(-b));

pt1.y = cvRound(y0 + 1000*(a));

pt2.x = cvRound(x0 - 1000*(-b));

pt2.y = cvRound(y0 - 1000*(a));

line( cdst, pt1, pt2, Scalar(0,0,255), 3, CV_AA);

}

#else

vector<Vec4i> lines;

HoughLinesP(dst, lines, 1, CV_PI/180, 50, 50, 10 );

for( size_t i = 0; i < lines.size(); i++ )

{

Vec4i l = lines[i];

line( cdst, Point(l[0], l[1]), Point(l[2], l[3]), Scalar(0,0,255), 3, LINE_AA);

}

#endif

imshow("source", src);

imshow("detected lines", cdst);

waitKey();

return 0;

}
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