poj2027
2017-02-09 09:13
253 查看
题目大意:
比较两个数的大小解题思路:
无代码如下:
#include<stdio.h> #include<string.h> int main() { int n,i,x,y; scanf("%d",&n); for(i=1;i<=n;i++) { scanf("%d%d",&x,&y); if(x>=y) { printf("MMM BRAINS\n"); } else { printf("NO BRAINS\n"); } } return 0; }
相关文章推荐
- 初学ACM - 组合数学基础题目PKU 1833
- POJ ACM 1001
- POJ ACM 1002
- 1611:The Suspects
- POJ1089 区间合并
- POJ 2159 Ancient Cipher
- POJ 2635 The Embarrassed Cryptographe
- POJ 3292 Semi-prime H-numbers
- POJ 2773 HAPPY 2006
- POJ 3090 Visible Lattice Points
- POJ-2409-Let it Bead&&NYOJ-280-LK的项链
- POJ-1695-Magazine Delivery-dp
- POJ1523 SPF dfs
- POJ-1001 求高精度幂-大数乘法系列
- POJ-1003 Hangover
- POJ-1004 Financial Management
- poj 1753 Flip Game
- poj 1328 Radar Installation
- poj 2528 Y2K Accounting Bug
- poj 3295 Tautology