a letter and a number

a letter and a number

http://acm.nyist.net/JudgeOnline/problem.php?pid=241

时间限制：3000 ms | 内存限制：65535 KB

难度：1

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

不要想的太复杂...

#include <stdio.h>
int main(int argc, char *argv[])
{
int n,b;
char a;
scanf("%d",&n);
while(n--){
scanf("\n%c %d",&a,&b);
if(a>='a')
printf("%d\n",-(a-'a'+1)+b);
else
printf("%d\n",a-'A'+1+b);
}
return 0;
}