Leetcode 191. Number of 1 Bits
2017-02-08 12:54
351 查看
Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.
s思路:
1. 移位就可以了!
For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.
s思路:
1. 移位就可以了!
class Solution { public: int hammingWeight(uint32_t n) { // int res=0; for(int i=0;i<32;i++){ if(n==0) break;//优化的不错:判断是否提前就等于0了,后面的操作就不必做了 res+=n&1; n>>=1; } return res; } };
相关文章推荐
- leetcode 191. Number of 1 Bits
- LeetCode 191. Number of 1 bits (位1的数量)
- LeetCode-191. Number of 1 Bits
- leetcode 191. Number of 1 Bits
- LeetCode191. Number of 1 Bits
- LeetCode 191. Number of 1 Bits
- 【LeetCode】 191. Number of 1 Bits
- Leetcode 191. Number of 1 Bits (Easy) (cpp)
- LeetCode 191. Number of 1 Bits
- LeetCode 191. Number of 1 Bits
- [LeetCode]191. Number of 1 Bits
- 【一天一道LeetCode】#191. Number of 1 Bits
- 191. Number of 1 Bits Leetcode Python
- [LeetCode]problem 191. Number of 1 Bits
- [LeetCode] 191. Number of 1 Bits 二进制数1的个数
- Leetcode 191. Number of 1 Bits
- 191. Number of 1 Bits--LeetCode Record
- 【一天一道LeetCode】#191. Number of 1 Bits
- 【leetcode】191. Number of 1 Bits(easy)
- LeetCode 191. Number of 1 Bits