1001_A+B for Matrices
2017-02-08 09:23
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//题目1001:A+B for Matrices //时间限制:1 秒内存限制:32 兆特殊判题:否提交:20447解决:8174 //题目描述: // This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns. //输入: // The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B. // The input is terminated by a zero M and that case must NOT be processed. //输出: // For each test case you should output in one line the total number of zero rows and columns of A+B. //样例输入: //2 2 //1 1 //1 1 //-1 -1 //10 9 //2 3 //1 2 3 //4 5 6 //-1 -2 -3 //-4 -5 -6 //0 //样例输出: //1 //5 #include "stdafx.h" #include "stdio.h" #include "string.h" #define MAX 11 int a[MAX][MAX]; int column[MAX]; int row[MAX]; int main() { //freopen("1001_data.in","r",stdin); //freopen("1001_data.out","w",stdout); int n,m,temp,count; while(scanf("%d %d",&m,&n) == 2 && m!=0) { for(int i = 0;i<MAX;i++) { column[i]=1; row[i]=1; } count = 0; for(int i = 0;i<m;i++) for(int j=0; j<n ;j++) { scanf("%d",&a[i][j]); } for(int i=0;i<m;i++) { for(int j=0;j<n;j++) { scanf("%d",&temp); a[i][j] += temp; if(a[i][j]!=0) { row[i] = 0; column[j] = 0; } } count += row[i]; } for(int j = 0;j<n;j++) { count += column[j]; } printf("%d\n",count); } return 0; }
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