iOS开发-获取字符串中多个相同字符的位置index

iOS开发-获取字符串中多个相同字符的位置index

#pragma mark - 获取这个字符串中的所有xxx的所在的index
- (NSMutableArray *)getRangeStr:(NSString *)text findText:(NSString *)findText
{

NSMutableArray *arrayRanges = [NSMutableArray arrayWithCapacity:3];

if (findText == nil && [findText isEqualToString:@""])
{

return nil;

}

NSRange rang = [text rangeOfString:findText]; //获取第一次出现的range

if (rang.location != NSNotFound && rang.length != 0)
{

[arrayRanges addObject:[NSNumber numberWithInteger:rang.location]];//将第一次的加入到数组中

NSRange rang1 = {0,0};

NSInteger location = 0;

NSInteger length = 0;

for (int i = 0;; i++)
{

if (0 == i)
{//去掉这个xxx

location = rang.location + rang.length;

length = text.length - rang.location - rang.length;

rang1 = NSMakeRange(location, length);

}
else
{

location = rang1.location + rang1.length;

length = text.length - rang1.location - rang1.length;

rang1 = NSMakeRange(location, length);

}

//在一个range范围内查找另一个字符串的range

rang1 = [text rangeOfString:findText options:NSCaseInsensitiveSearch range:rang1];

if (rang1.location == NSNotFound && rang1.length == 0)
{

break;

}
else//添加符合条件的location进数组

[arrayRanges addObject:[NSNumber numberWithInteger:rang1.location]];

}

return arrayRanges;

}

return nil;

}