B - USB vs. PS/2 CodeForces - 762B （贪心）

Due to the increase in the number of students of Berland State University it was decided to equip a new computer room. You were given the task of buying mouses, and you have to spend as little as possible. After all, the country is in crisis!

The computers bought for the room were different. Some of them had only USB ports, some — only PS/2 ports, and some had both options.

You have found a price list of a certain computer shop. In it, for m mouses it is specified the cost and the type of the port that is required to plug the mouse in (USB or PS/2). Each mouse from the list can be bought
at most once.

You want to buy some set of mouses from the given price list in such a way so that you maximize the number of computers equipped with mouses (it is not guaranteed that you will be able to equip all of the computers), and in case of equality of this value
you want to minimize the total cost of mouses you will buy.

Input

The first line contains three integers a, b and c (0 ≤ a, b, c ≤ 105)
 — the number of computers that only have USB ports, the number of computers, that only have PS/2 ports, and the number of computers, that have both options, respectively.

The next line contains one integer m (0 ≤ m ≤ 3·105)  — the number of mouses in the price list.

The next m lines each describe another mouse. The i-th line contains first integer vali (1 ≤ vali ≤ 109)
 — the cost of the i-th mouse, then the type of port (USB or PS/2) that is required to plug the mouse in.

Output

Output two integers separated by space — the number of equipped computers and the total cost of the mouses you will buy.

Example

Input

2 1 1
4
5 USB
6 PS/2
3 PS/2
7 PS/2

Output

3 14

Note

In the first example you can buy the first three mouses. This way you will equip one of the computers that has only a USB port with a USB mouse, and the two PS/2 mouses you will plug into the computer with PS/2 port and the computer with both ports.

题目大意：有两种鼠标，需要供给三种电脑，其中有一种电脑两种鼠标都能用，而其他两种电脑只能用两种鼠标的一种，问你在尽量使最多电脑配备鼠标的情况下，花费最少。

题目分析：

   一个挺好想的贪心问题，但是在实现的过程中有点饶人，还好。就是尽量排个序尽量优先给那些只能用一种鼠标的电脑，满足尽量使最多电脑配备鼠标的要求，而排序满足花费最少，所以是个还可以的贪心问题。

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define maxn 1000005
using namespace std;
long long m[maxn],n[maxn],w[maxn];
int main(){
long long a,b,c;
char ch[10];
while((scanf("%lld%lld%lld",&a,&b,&c))!=EOF){
long long t;
scanf("%lld",&t);
long long p=0,q=0,r,sum1=0,sum2=0,f;
for(int i=0;i<t;i++){
scanf("%lld",&f);
scanf("%s",ch);
if(ch[0] == 'U')
m[p++]=f;
else n[q++]=f;
}
sort(m,m+p);//升序排列
sort(n,n+q);//
long long i,j;
long long l=0;
for(i=0;i<a&&i<p;i++){
sum2+=m[i];
sum1++;
}
while(m[i]){
w[l++]=m[i++];
}
for(i=0;i<b&&i<q;i++){
sum2+=n[i];
sum1++;
}
while(n[i])
w[l++]=n[i++];
sort(w,w+l);
for(int i=0;i<c&&i<l;i++){
sum2+=w[i];
sum1++;
}
printf("%lld %lld\n",sum1,sum2);
}
return 0;
}