UVa1586 - Molar mass

//UVa1586 - Molar mass
//给出一种由C, H, O, N 四种原子构成的分子式，求分子量
//#define A1 //无法处理换行问题(scanf)
//#define A2 //临界问题有BUG(sscanf)
#define A3 //只考虑两位即可AC，直接暴力
//#define A4 //考虑多位数有BUG

#ifdef A1
#include<stdio.h>
int main(){
//freopen("data.in","r",stdin);
int T;
scanf("%d",&T);
getchar();
while(T--){
char ch, ch2 = 'A'; int num; float M, ans = 0;
//无法处理换行问题
//while((ch2=getchar()) != EOF){
while(scanf("%c",&ch2) == 1){
if(ch2 == '\n'){if(ch >= 'C')ans += M; break;}
else ch = ch2;
if(ch == 'C') M = 12.01;
if(ch == 'H') M = 1.008;
if(ch == 'O') M = 16.00;
if(ch == 'N') M = 14.01;
if(scanf("%d",&num) != 1) ans += M;
else ans += M*num;
}
printf("%.3f\n", ans);
}
return 0;
}
#endif

#ifdef A2
#include<stdio.h>
#include<string.h>
#define maxn 20
int bits(int x){
if(x == 0)return 1;
int count = 0;
while(x>0){ count++; x/=10;}
return count;
}
int main(){
freopen("data.in","r",stdin);
int T;
scanf("%d",&T);
getchar();
while(T--){
int num; float M, ans = 0;
char str[maxn];
fgets(str,maxn,stdin);
//scanf("%s",str);
for(int i = 0; i<strlen(str); i++){
if(str[i] ==
4000
'C') M = 12.01;
if(str[i] == 'H') M = 1.008;
if(str[i] == 'O') M = 16.00;
if(str[i] == 'N') M = 14.01;
if(i == strlen(str)-1 && str[i]>='C'){ ans += M; break;}
if(sscanf(&str[i+1],"%d",&num) != 1) ans += M;
else {
i += bits(num);
ans += M*num;
}
}
printf("%.3f\n", ans);
}
return 0;
}
#endif

#ifdef A3
#include<stdio.h>
#include<string.h>
#include<ctype.h>
#define maxn 100
int main(){
//freopen("data.in","r",stdin);
int T;
scanf("%d",&T);
while(T--){
char s[maxn]; scanf("%s",s);
int n, a[4], len = strlen(s);
memset(a,0,sizeof(a));
for(int i = 0; i<len; i++){
if(s[i] == 'C') n = 0;
if(s[i] == 'H') n = 1;
if(s[i] == 'O') n = 2;
if(s[i] == 'N') n = 3;
if(s[i]>='C')
if(isdigit(s[i+1]) && isdigit(s[i+2])) a
+= 10*(s[i+1]-'0')+(s[i+2]-'0');
else a
+= isdigit(s[i+1])? s[i+1]-'0': 1;
}
printf("%.3f\n", 12.01*a[0]+1.008*a[1]+16.00*a[2]+14.01*a[3]);
}
return 0;
}
#endif

#ifdef A4
#include<stdio.h>
#include<string.h>
int co(int cot){int add42=1; while(--cot)add42 *= 10; return add42;}
int main(){
freopen("data.in","r",stdin);
int T;
scanf("%d",&T);
getchar();
while(T--){
char s[20];int a[4],n;
memset(a,0,sizeof(a));
//获取输入
scanf("%s",s);
//处理数据
for(int i = 0; i < strlen(s); i++){
if(s[i] > 57){//存储个数
if(s[i] == 'C'){n=0;a
++;}
if(s[i] == 'H'){n=1;a
++;}
if(s[i] == 'O'){n=2;a
++;}
if(s[i] == 'N'){n=3;a
++;}
}else{
int count = 0;//记录数字位数
for(int j = 0; ; j++){
if(s[i+j] <= 57)count++;
else break;
printf("%d\n",j);
}
while(count--){a
+= (s[i+count]-'1')*co(count);printf("%d ",count);}
}
}
//输出
printf("%.3f\n",12.01*a[0]+1.008*a[1]+16.00*a[2]+14.01*a[3]);
}
return 0;
}
#endif
/*测试数据:
4
C
C6H5OH
NH2CH2COOH
C12H22O11

12.010
94.108
75.070
342.296
*/