【LeetCode】 376. Wiggle Subsequence
2017-01-23 02:30
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A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A
sequence with fewer than two elements is trivially a wiggle sequence.
For example,
are alternately positive and negative. In contrast,
not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original
order.
Examples:
Follow up:
Can you do it in O(n) time?
sequence with fewer than two elements is trivially a wiggle sequence.
For example,
[1,7,4,9,2,5]is a wiggle sequence because the differences (6,-3,5,-7,3)
are alternately positive and negative. In contrast,
[1,4,7,2,5]and
[1,7,4,5,5]are
not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original
order.
Examples:
Input: [1,7,4,9,2,5] Output: 6 The entire sequence is a wiggle sequence. Input: [1,17,5,10,13,15,10,5,16,8] Output: 7 There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8]. Input: [1,2,3,4,5,6,7,8,9] Output: 2
Follow up:
Can you do it in O(n) time?
public class Solution { public int wiggleMaxLength(int[] nums) { int num1 = 1, num2 = 1; for (int i = 1; i < nums.length; i++) { if (nums[i] > nums[i - 1]) { num1 = num2 + 1; } else if (nums[i] < nums[i - 1]){ num2 = num1 + 1; } } return Math.min(nums.length, Math.max(num1, num2)); } }
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